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timurjin [86]
3 years ago
12

Home living magazine found that 66% of new puppy owners greet their puppy before greeting their spouse or children when they ret

urn home at the end of the workday. Suppose that 12 puppy owners are selected at random
1.Show that four requirements for a binomial setting are satisfied.
2 Find the probability that exactly seven of the 12 puppy owners greet their dog first when they arrive home.
3.Find the probability that at least 5 of the dog 12 dog owners greet their puppy first when they arrive home.
4.Find the mean and standard deviation for the random variable X in this problem
Mathematics
1 answer:
mihalych1998 [28]3 years ago
5 0

Answer:

idk

Step-by-step explanation:

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Juanita and Nina are bowling together. The probability of Juanita getting a strike next game is 24%. The probability of Nina get
ASHA 777 [7]

Answer:

(Choice A)

Juanita gets a strike next game.'

Step-by-step explanation:

Your question is obviously incomplete.

Complete question is:

Juanita and Nina are bowling together. The probability of Juanita getting a strike next game is 24%. The probability of Nina getting a strike next game is 0.17. Which of these events is more likely?

(Choice A)

Juanita gets a strike next game.'

(Choice B)

Nina gets a strike next game.

(Choice C)

Neither. Both events are equally likely.

Answer:

Probability of Juanita : P(J)= 24% => 0.24

probability of Nina getting a strike next game: P(N) = 0.17

As you can see 0.24 > 0.17 ----> P(J)>P(N)

Thus it can be concluded that Juanita gets a strike next game is more likely.

so, choice A

4 0
3 years ago
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15. Madison invested in a certificate of deposit for 4 years at a 6% interest rate. At the end of the 4 years, the value
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Answer:

2455.49

Step-by-step explanation:

3100=x(1+.06)^4\\x=2455.490356

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3 years ago
C. Identify the following as a constant, linear, or absolute value
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Answer:

here is the answer bae. Feel free to ask for more

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Solve equation.<br> 2x-5y=20
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If you solve for x you get:
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