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timurjin [86]
2 years ago
12

Home living magazine found that 66% of new puppy owners greet their puppy before greeting their spouse or children when they ret

urn home at the end of the workday. Suppose that 12 puppy owners are selected at random
1.Show that four requirements for a binomial setting are satisfied.
2 Find the probability that exactly seven of the 12 puppy owners greet their dog first when they arrive home.
3.Find the probability that at least 5 of the dog 12 dog owners greet their puppy first when they arrive home.
4.Find the mean and standard deviation for the random variable X in this problem
Mathematics
1 answer:
mihalych1998 [28]2 years ago
5 0

Answer:

idk

Step-by-step explanation:

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What is the best defenition for sample as used in in statistics​
leva [86]

Answer: Well sampling is the process of choosing a representative sample from a target population and collecting data from that sample in order to understand something about the population as a whole. A data sample is a set of data collected and the world selected from a statistical population by a defined procedure.

Step-by-step explanation:

8 0
3 years ago
Answer each of the questions for the following diagram:
sweet [91]

Answer:

1.  Complimentary angles

2.  3x+20 = 10x-15: x = 5

3.  I'm not sure on part 3, sorry.



5 0
3 years ago
Can someone take 3 min for there time and help me with this please??
seropon [69]
Since the left side of the equation says f(5), then plug in 5 for x. 

So, it is: 
              
-4|5| + 3
= -20 + 3
= 23 
4 0
2 years ago
The graph of the equation y=7x-3 has what slope?
Nikitich [7]
The slope of the line would be 7 
3 0
3 years ago
Read 2 more answers
Internet company Gurgle is carrying out testing on the efficiency of its search engine. A sample of 31 searches have been carrie
Mrac [35]

Answer:

d. Approximate the standard normal distribution with the Student's t distribution

(0.2199 ; 0.2327)

Step-by-step explanation:

Given that :

Sample size, n = 31

Sample mean, xbar = 0.2258

Sample standard deviation, s = 0.0188

Confidence interval (C. I) :

xbar ± margin of error

Margin of Error : Tcritical * s/sqrt(n)

Degree of freedom, df = n - 1 = 31 - 1 = 30

Tcritical value :

T0.05/2, 30 = 2.042

Margin of Error = 2.042 * 0.0188/sqrt(31)

Margin of Error = 0.0068949

C. I = 0.2258 ± 0.0068949

Lower boundary : (0.2258 - 0.006895) = 0.2189

Upper boundary : (0.2258 - 0.006895) = 0.2327

(0.2199 ; 0.2327)

3 0
2 years ago
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