Ammonia is NH3. The molar mass of NH3 is 17.0307g.
(1.2*10^3)/17.0307=70.46 moles of NH3.
If you are using significant figures, it is 70. moles of NH3.
0.125 g=(0.125 g)(1000 mg/1g)=125 mg.
Then, we need 125 mg of ampicillin.
5 ml of liquid suspension contains 250 mg of ampicilling , therefore:
5 ml----------------250 mg of ampicilling
x--------------------125 mg of ampicilling
x=(5 ml * 125 mg of ampicilling) / 250 mg of ampicilling=2.5 ml
Answer: we require 2.5 ml
Explanation:
Meso compounds are optically inactive stereoisomers. Despite of having chiral carbon, they do not show optical activity because it has a plane of symmetry in its structure itself. It is superposable on its mirror image.
Aldo sugars on reaction which reducing agents such as , NaBH₄ reduces the carbonyl group in the sugar to alcohol and gives corresponding alditol.
<u>The D- aldohexose which on reduction gives a meso alditol are allose and galactose. </u>
<u>The structure is shown in the image below. Thus, in allitol and galactitol formed have internal plane of symmetry which makes the optically inactive.</u>
As you go down a group, the atoms get bigger. The bigger the atom, the more unstable it is. The more unstable it is, the more reactive the atom will be. So, as you go down a group, the nonmetals will become more reactive.
Answer:
second option and last option
Explanation:
Know how to do an electron configuration. This is correct because it adds up to 8 and is in the correct order.
All valence electrons are in the last shell. In this case, 2p is the last shell.