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Elanso [62]
3 years ago
12

What is the best kind of cleaning agent to use for cleaning burned-on grease?

Chemistry
2 answers:
gulaghasi [49]3 years ago
6 0
Vinegar and a cloth for stainless steel then lemon tree for everythingelse
lakkis [162]3 years ago
4 0

soap and water would be the best soak it in water for 20 miuntes then wash it

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Suppose hydrochloric acid reacts with potassium sulfite yielding water, sulfur dioxide, and potassium chloride. Suppose 4 moles
anzhelika [568]

Answer:

128 grams of sulfur dioxide are produced.

Explanation:

2HCl+K_2SO_3\rightarrow SO_2+2KCl+H_2O

Moles of HCl = 4 moles

According to reaction, 2 moles of HCl gives 1 mole of sulfur dioxide gas.

Then 4 moles of HCl will give:

\frac{1}{2}\times 4 moles=2 moles of sulfur dioxide gas.

Mass of sulfur dioxide gas = 2 mol × 64 g/mol = 128 g

128 grams of sulfur dioxide are produced.

4 0
2 years ago
How much pressure would 0.8 moles of a gas at 370K exert if it occupied 17.3L of space
dezoksy [38]

Answer:

1.40 atm is the pressure for the gas

Explanation:

An easy problem to solve with the Ideal Gases Law:

P . V = n . R .T

T° = 370K

V = 17.3L

n = 0.8 mol

Let's replace data → P . 17.3L = 0.8mol . 0.082L.atm/mol.K . 370K

P = (0.8mol . 0.082L.atm/mol.K . 370K) / 17.3L = 1.40 atm

7 0
2 years ago
Read 2 more answers
Which gas variable has to do with the amount of collisions of gas particles has?
Firlakuza [10]
The answer is temperature
3 0
3 years ago
A solid with a mass of Mgrams is melted by heating it. After a half-hour, the solid is
Lerok [7]

Answer:

equal to M

Explanation:

The mass of the fully melted mass and the initial solid will be the same. So, the mass of the melt is equal to M.

Mass is the amount of matter contained within a substance. Since only the phase changed and the amount of matter is still the same, the mass of the molten phase and the solid phase will remain the same.

We are correct to say that in the heating process no mass was destroyed or added in melting the solid.

A simple phase change that preserved the mass only occurred.

7 0
2 years ago
How many milliliters of 5.0 M NaOH are needed to exactly neutralize 40. milliliters of 2.0 M HCl?
zubka84 [21]

Answer:

16mL

Explanation:

Using the following formula;

CaVa = CbVb

Where;

Where

Ca = concentration/molarity of acid (M)

Va = volume of acid (mL)

Cb = concentration/molarity of base (M)

Vb = volume of base (mL)

According to the information provided in this question;

Ca (HCl) = 2M

Cb (NaOH) = 5M

Va (HCl) = 40mL

Vb (NaOH) = ?

Using CaVa = CbVb

Vb = CaVa/Cb

Vb = 2 × 40/5

Vb = 80/5

Vb = 16mL

5 0
2 years ago
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