<h3>
Answer: 4.25 g/ml %</h3>
Explanation:
weight/volume percentage concentration = (mass in g ÷ volume) × 100
= (0.850 g ÷ 20 ml) × 100
= 4.25 g/ml %
∴ the weight/volume percentage concentration of the sucrose solution is 4.25 g/ml %.
The Balanced Chemical Equation is as follow;
4 KO₂ + 2 CO₂ → 2 K₂CO₃ + 3 O₂
First find out the Limiting Reagent,
According to equation,
284 g (4 moles) KO₂ reacted with = 44.8 L (2 moles) of CO₂
So,
27.9 g of KO₂ will react with = X L of CO₂
Solving for X,
X = (44.8 L × 27.9 g) ÷ 284 g
X = 4.40 L of CO₂
Hence, to consume 27.9 g of KO₂ only 4.40 L CO₂ is required, while, we are provided with 29 L of CO₂, it means CO₂ is in excess and KO₂ is is limited amount, Therefore, KO₂ will control the yield of K₂CO₃. So,
According to eq.
284 g (4 moles) KO₂ formed = 138.2 g of K₂CO₃
So,
27.9 g of KO₂ will form = X g of K₂CO₃
Solving for X,
X = (138.2 g × 27.9 g) ÷ 284 g
X = 13.57 g of K₂CO₃
So, 13.57 g of K₂CO₃ formed is the theoretical yield.
%age Yield = 13.57 / 21.8 × 100
%age Yield = 62.24 %
Answer:
Number of Protons 48
Number of Neutrons 64
Number of Electrons 48
Explanation:
The mass number of an atom is the sum of the number of protons and neutrons in the nucleus of that atom
D. Electrons
Atoms can share their electrons in order to create bonds with other atoms
Answer:
D is the answer to your question in my opinion
