When ethyl-2-methylpropanoate is treated with sodium ethoxide in ethanol, there is no observable reaction. Explain this observat
ion.
1 answer:
Answer:
No net change in reaction occurs in this nucleophilic acyl subtitution reaction
Explanation:
Sodium ethoxide in ethanol gives nucleophilic acyl substitution reaction with ethyl-2-methylpropanoate.
Here ethoxide group replaces an ethoxide group from ester through addition-ellimination pathway.
So, ultimately, the product of this reaction is identical with reactant i.e. ethyl-2-methylpropanoate is reproduced.
Hence one might observe no change during reaction as product and reactant of this reaction are same.
Mechanistic pathway has been shown below.
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<u>Answer:</u> The mass of calcium chloride formed is 15.21 grams.
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
- <u>For calcium carbonate:</u>
Given mass of calcium carbonate = 32.0 g
Molar mass of calcium carbonate = 100 g/mol
Putting values in equation 1, we get:
- <u>For hydrochloric acid:</u>
Given mass of hydrochloric acid = 10.0 g
Molar mass of hydrochloric acid = 36.5 g/mol
Putting values in equation 1, we get:
The given chemical equation follows:
By Stoichiometry of the reaction:
2 moles of hydrochloric acid reacts with 1 mole of calcium carbonate
So, 0.274 moles of hydrochloric acid will react with = of calcium carbonate
As, given amount of calcium carbonate is more than the required amount. So, it is considered as an excess reagent.
Thus, hydrochloric acid is considered as a limiting reagent because it limits the formation of product.
By Stoichiometry of the reaction:
2 moles of hydrochloric acid produces 1 mole of calcium chloride.
So, 0.274 moles of hydrochloric acid will produce = of calcium chloride.
Now, calculating the mass of calcium chloride from equation 1, we get:
Molar mass of calcium chloride = 111 g/mol
Moles of calcium chloride = 0.137 moles
Putting values in equation 1, we get:
Hence, the mass of calcium chloride formed is 15.21 grams.