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3 years ago

WORTH 99 POINTS

Chemistry

2 answers:

Gennadij [26K]3 years ago

8 0

desertification, urbanization, and climate change(more carbon dioxide).

stealth61 [152]3 years ago

8 0

Answer:

Desertification and climate change and urbanization

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In the wintertime, you decide to buy a helium balloon at Dollar Tree. It is fully

Gemiola [76]

Answer:

The reason that the balloon shrinks is because when the temperature drops, helium becomes more dense then it already is. So what happens is that its molecules lose energy, slows down and moves closer together to conserve heat and this decreases the volume inside the balloon because the helium molecules are moving closer together, rather than outward toward the shell of the balloon which cause the balloon to swell then shrink. The gas law that causes this to happen is the Charles law.

Explanation:

5 0

3 years ago

Read 2 more answers

What amount of energy is required to change a spherical drop of water with a diameter of 1.80 mm to three smaller spherical drop

Gekata [30.6K]

This is a straightforward question related to the surface energy of the droplet.

You know the surface area of a sphere is 4π r² and its volume is (4/3) π r³. 

With a diameter of 1.4 mm you have an original droplet with a radius of 0.7 mm so the surface area is roughly 6.16 mm² (0.00000616 m²) and the volume is roughly 1.438 mm³. 

The total surface energy of the original droplet is 0.00000616 * 72 ~ 0.00044 mJ 

The five smaller droplets need to have the same volume as the original. Therefore 

5 V = 1.438 mm³ so the volume of one of the smaller spheres is 1.438/5 = 0.287 mm³. 

Since this smaller volume still has the volume (4/3) π r³ then r = cube_root(0.287/(4/3) π) = cube_root(4.39) = 0.4 mm. 

Each of the smaller droplets has a surface area of 4π r² = 2 mm² or 0.0000002 m². 

The surface energy of the 5 smaller droplets is then 5 * 0.000002 * 72.0 = 0.00072 mJ 
From this radius the surface energy of all smaller droplets is 0.00072 and the difference in energy is 0.00072- 0.00044 mJ = 0.00028 mJ. 

Therefore you need roughly 0.00028 mJ or 0.28 µJ of energy to change a spherical droplet of water of diameter 1.4 mm into 5 identical smaller droplets.

7 0

3 years ago

Heat is transferred directly from a heat reservoir at 200 C to another heat reservoir at 5C. If the amount of heat transferred i

Daniel [21]

Answer:

ΔS=0.148 KJ/K

Explanation:

Given that

Q = 100 KJ

T₁=200°C

T₁=200+273 = 437 K

T₂=5°C

T₂=5 + 273 = 278 K

Reservoir 1 is rejecting heat that is why it taken as negative while the reservoir 2 is gaining the heat that is why it is taken as positive.

So the total change in entropy given as

ΔS= - Q/T₁ + Q/T₂

ΔS= - 100/473 + 100/278 KJ/K

ΔS=0.148 KJ/K

4 0

3 years ago

Mixture of 120 grams of KClO3 and 300 grams of water until all of the KClO3 has dissolved. At what temperature does this occur?

lozanna [386]

240°C is required to dissolve 120 grams of KClO₃ in 300 g of water.

Explanation:

As per the solubility curve graph of different salts dissolved in 100 g of water, it can be noted that the KClO₃ gets saturated at 100 °C with the solubility of 59 g in it. But here the water is taken as 300 g and the salt is taken as 120 g. The graph shows the solubility of grams of salt in 100 g of water.

So, then we have to find what is the gram of salt present in 100 g of water for the present sample.

300 g of water contains 120 grams of salt.

Then, 1 g of water will contain $\frac{120}{300}$ g of salt.

Then, 100 g of water will contain $\frac{120}{300}*100$ of salt. This means, 100 g of water will contain 40 g of salt in it.

Then, if we check the graph, the corresponding x-axis point on the curve for the y-axis value of 40 g will give us the temperature required to dissolve the salt in water. So 80°C will be required to dissolve 40 g of salt in 100 g of water.

Then, in order to get the temperature required to dissolve 120 g in 300 g of water, multiply the temperature by 3, which will give the result as 80×3=240 °C.

So, 240°C is required to dissolve 120 grams of KClO₃ in 300 g of water.

8 0

3 years ago

1. An acid will have the suffix “–ic acid” at the end of its name when the negative

Nimfa-mama [501]

An acid will have the suffix “–ic acid” at the end of its name when the negative ion has a suffix -ide.

An acid will have the suffix “–ous acid” at the end of its name when the negative ion has a suffix -ite.

This is defined as a chemical substance which can react with a base to form a salt in a reaction.

The appropriate acid suffixes and conditions is however correctly given above.

Read more about Acid here brainly.com/question/2183107

4 0

2 years ago