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3 years ago

PLEASEEE HELPPPP I WILL AWARD BRAINLIEST

Chemistry

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vampirchik [111]3 years ago

3 0

Yesssirrrrrrrrr someone answer

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Solid cesium iodide has the same kind of crystal structure as CsCl which is pictured below: If the edge length of the unit cell

Assoli18 [71]

The question is incomplete, here is the complete question:

Solid cesium iodide has the same kind of crystal structure as CsCl which is pictured below: If the edge length of the unit cell is 456.2 pm, what is the density of CsI in $g/cm^3$

The image is attached below.

Answer: The density of CsI is $9.09g/cm^3$

Explanation:

To calculate the density of metal, we use the equation:

$\rho=\frac{Z\times M}{N_{A}\times a^{3}}$

where,

$\rho$ = density

Z = number of atom in unit cell = 2 (BCC)

M = atomic mass of CsI = 259.8 g/mol

$N_{A}$ = Avogadro's number = $6.022\times 10^{23}$

a = edge length of unit cell = $456.2pm=456.2\times 10^{-10}cm$ (Conversion factor: $1cm=10^{10}pm$ )

Putting values in above equation, we get:

$\rho=\frac{1\times 259.8}{6.022\times 10^{23}\times (456.2\times 10^{-10})^3}\\\\\rho=9.09g/cm^3$

Hence, the density of CsI is $9.09g/cm^3$

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3 years ago

Amount of valence electrons KMnO4

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8 0

3 years ago

PLEASE HELP!!!! WILL MARK BRAINLIEST

11111nata11111 [884]

This is sulfer, sulfer is the atom with 16 protons, neutrons and electrons.

5 0

3 years ago

What is the simplified value of the exponent expression 16^1/4

Sliva [168]

Answer: 2

Justitification:

1) Property:

$a^{(1/b)} = \sqrt[b]{a}$

Therefore:

$16^{1/4}= \sqrt[4]{16}$

2) 16 = 2⁴

3) Property

$\sqrt[n]{a^n} =a^{n/n}=a$

Therefore:

$\sqrt[4]{2^4} =2^{4/4}=2$

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3 years ago

The equation for the formation of ammonia from nitrogen and hydrogen is shown below. What is the formula for the equilibrium con

WINSTONCH [101]

First, make sure to balance your equation.

3H2(g) + N2(g) ⇄ 2NH3(g)

Now, you can write your Kc expression. Remember that Kc is products over reactants, and the exponent for each product or reactant is based on its coefficient.

Kc = [NH3]^2 / [H2]^3[N2]

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3 years ago