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Simora [160]
3 years ago
5

According to the following reaction, how many grams of carbon tetrachloride will be formed upon the complete reaction of 27.7 gr

ams of chlorine gas with excess carbon disulfide? carbon disulfide (s) + chlorine (g) carbon tetrachloride (l) + sulfur dichloride (s) grams carbon tetrachloride
Chemistry
1 answer:
Black_prince [1.1K]3 years ago
7 0

Answer: 15.0 g of CCl_4 will be formed upon the complete reaction of 27.7 grams of chlorine gas with excess carbon disulfide

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} Cl_2=\frac{27.7g}{71g/mol}=0.390moles

The balanced chemical reaction is:

CS_2(g)+4Cl_2(g)\rightarrow CCl_4(l)+2SCl_2(s)

Cl_2 is the limiting reagent as it limits the formation of product and CS_2 is the excess reagent.

According to stoichiometry :

4 moles of Cl_2 give=  1 mole of CCl_4

Thus 0.390 moles of  will give = \frac{1}{4}\times 0.390=0.0975moles of CCl_4

Mass of CCl_4=moles\times {\text {Molar mass}}=0.0975\times 154=15.0g

Thus 15.0 g of CCl_4 will be formed upon the complete reaction of 27.7 grams of chlorine gas with excess carbon disulfide

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