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Nady [450]
3 years ago
15

-Material A has a melting point of 34°C whereas Material B has a melting point of 56°C. Both materials have been placed in an ov

en at 50°C Describe the state of each material after being being in the oven for a period of time.
I'm confused, if material B is on for the same amount of time does that mean that it has liquified and material A has melted slightly?
Chemistry
1 answer:
attashe74 [19]3 years ago
6 0

Answer:

Explanation:

Material A has a melting point of 34°C

Material B has a melting point of 56°C

Both materials, lets say a metal have been subjected to a temperature of 50°C

After a period of time, both of them would have melted to their liquid state.

The atoms of the solids would vibrates and the bonds would begin to break to form melt.

Material A would be the first to melt as it has a lower melting point. The lower the melting point, the faster and quicker it would reach its melting temperature.

Material B would need to accumulate more heat and its temperature would continue to rise for the phase change to occur. As it reaches the 50°C mark, the bonds are set free and a melt forms.

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25.00 mL of a H2SO4 solution with an unknown concentration was titrated to a phenolphthalein endpoint with 28.11 mL of a 0.1311
LuckyWell [14K]

Answer:

Concentration of the H₂SO₄ solution is 0.0737 M

Explanation:

Equation of the neutralization reaction between the acid, H₂SO₄, and the base, NaOH, is given below:

H₂SO₄ + 2NaOH -----> Na₂SO₄ + 2H₂O

From the above equation, one mole of acid requires 2 moles of base for complete neutralization which occurs at phenolphthalein endpoint.

mole ratio of acid to base, nA/nB = 1:2

Concentration of the base, Cb = 0.1311 M

Volume of base, Vb, = 28.11 mL

Concentration of acid, Ca = ?

Volume of acid, Va + 25.0 mL

Using the formula, CaVa/CbVb = nA/nB

making Ca subject of the formula, Ca = Cb*Vb*nA/Va*nB

substituting the values into the equation

Ca = (0.1311 * 28.11 * 1) / 25.0 * 2 = 0.0737 M

Therefore, concentration of the H₂SO₄ solution is 0.0737 M

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4 years ago
When multiplying numbers in scientific notation what do you do with exponents?
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Answer:

Subtract them.

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I was actually learned about this in school just found an source.

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