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Nady [450]
3 years ago
15

-Material A has a melting point of 34°C whereas Material B has a melting point of 56°C. Both materials have been placed in an ov

en at 50°C Describe the state of each material after being being in the oven for a period of time.
I'm confused, if material B is on for the same amount of time does that mean that it has liquified and material A has melted slightly?
Chemistry
1 answer:
attashe74 [19]3 years ago
6 0

Answer:

Explanation:

Material A has a melting point of 34°C

Material B has a melting point of 56°C

Both materials, lets say a metal have been subjected to a temperature of 50°C

After a period of time, both of them would have melted to their liquid state.

The atoms of the solids would vibrates and the bonds would begin to break to form melt.

Material A would be the first to melt as it has a lower melting point. The lower the melting point, the faster and quicker it would reach its melting temperature.

Material B would need to accumulate more heat and its temperature would continue to rise for the phase change to occur. As it reaches the 50°C mark, the bonds are set free and a melt forms.

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6 0
2 years ago
Read 2 more answers
How many unpaired electrons are present in a ground-state atom from each of the following groups?
musickatia [10]

For 7A(17) :

Electronic configuration ns^2 np^5

So, there are 5 unpaired electrons present in group 7A(17).

<h3>What are Unpaired Electrons?</h3>
  • An unpaired electron is an electron that doesn't form part of an electron pair when it occupies an atom's orbital in chemistry.
  • Each of an atom's three atomic orbitals, designated by the quantum numbers n, l, and m, has the capacity to hold a pair of two electrons with opposing spins.
  • Unpaired electrons are extremely uncommon in chemistry because an object carrying an unpaired electron is typically quite reactive. This is because the production of electron pairs, whether in the form of a chemical bond or as a lone pair, is frequently energetically advantageous.
  • They play a crucial role in describing reaction pathways even though they normally only appear momentarily during a reaction on a thing called a radical in organic chemistry.

To learn more about unpaired electrons with the given link

brainly.com/question/14356000

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6 0
2 years ago
Which statements describes Newton's law of universal gravitation ?
IrinaK [193]

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8 0
3 years ago
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A solution of CaCl 2 in water forms a mixture that is 42.0 % calcium chloride by mass. If the total mass of the mixture is 839.6
Lerok [7]

Answer : The masses of calcium chloride and water used were, 352.6 g and 487.0 g.

Explanation :

As we are given that 42.0 % calcium chloride by mass that means 42.0 grams of calcium chloride present in 100 grams of solution.

In the solution or mixture, 42.0 % calcium chloride and 58.0 % (100-42.0=58.0) water.

Now we have to determine the mass of calcium chloride for 839.6 grams of solution.

As, 100 grams of solution contains 42.0 grams of calcium chloride

So, 839.6 grams of solution contains \frac{42.0}{100}\times 839.6=352.6 grams of calcium chloride

Thus, the mass of calcium chloride used is, 352.6 grams.

Now we have to determine the mass of water.

Mass of water = Mass of solution - Mass of calcium chloride

Mass of water = 839.6 g - 352.6 g

Mass of water = 487.0 g

Thus, the mass of water used is, 487.0 grams.

6 0
3 years ago
A person tries to heat up her bath water by adding 5.0 l of water at 80c to 60 l of water at 30c. what is the final temperature
Sophie [7]
We can calculate the final temperature from this formula :

when Tf = (V1* T1) +(V2* T2) / (V1+ V2)

when V1 is the first volume of water = 5 L 

and V2 is the second  volume of water = 60 L

and T1 is the first temperature of water in Kelvin = 80 °C +273 = 353 K

and T2 is the second temperature of water in Kelvin =  30°C + 273= 303 K

and Tf is the final temperature of water in Kelvin 

so, by substitution:

Tf = (5 L * 353 K ) + ( 60 L * 303 K) / ( 5 L + 60 L)

     = 1765 + 18180 / 65 L

     = 306 K
     = 306 -273 = 33° C

8 0
2 years ago
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