Answer:
(a)The molar mass of the gene fragment is 18220.071g/mol = 18.22 kg/mol
(b)The freezing point for the aqueous solution is C
Explanation:
The osmotic pressure (π) is given by the following equation:
= Concentration of solution
R = universal gas constant = 62.364
T = temperature
Weight of solute = w = 10.0 mg
Let the molecular weight of the solute be m g/mol.
Concentration =
m = 18220.071g/mol
Therefore, the molar mass of the gene fragment is 18220.071g/mol = 18.22 kg/mol
m is the molality of the solution.
m = mol/kg
= C
The freezing point for the aqueous solution is C
<u>Answer:</u>
<em>The substance is NaOH</em>
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<u>Explanation:</u>
To find the number of atoms of each element we multiply coefficient and the subscript
For example contains
5 × 1 = 5,Ca atoms and
5 × 2 = 10, Cl atoms
Sodium hydroxide is NaOH which contains
1, Na atom and
1, O atom and
1, H atom
Hence the ratio is 1 : 1 : 1
Volume never changes no matter the phase change.
Answer : The freezing point of the solution is, 260.503 K
Solution : Given,
Mass of methanol (solute) = 215 g
Mass of water (solvent) = 1000 g = 1 kg (1 kg = 1000 g)
Freezing depression constant =
Formula used :
where,
= freezing point of water =
= freezing point of solution
= freezing point constant
= mass of solute
= mass of solvent
= molar mass of solute
Now put all the given values in the above formula, we get
By rearranging the terms, we get the freezing point of solution.
Therefore, the freezing point of the solution is, 260.503 K
Answer:
honey and water, butanol and water, and potassium chloride and water.
Explanation: