Question

The shoe is in contact with the initially nearly stationary 0.500 kg football for 20.0 ms. What average force is exerted on the football in Newtons to give it a velocity of 22 m/s?

Answer 1

If v=22m/s after0.02s then acceleration was
22/0.02=1100m/s^2
Now, F=ma=(0.5)(1100)=550N

Answer 2

Answer:

F = 550 N

Explanation:

As we know that acceleration of the football is given as

$a = \frac{v_f - v_i}{\Delta t}$

here we know that

$v_i = 0$

$v_f = 22 m/s$

$\Delta t = 20 ms$

now we have

$a = \frac{22 - 0}{20 \times 10^{-3}}$

$a = 1100 m/s^2$

now the force exerted on the ball is given as

$F = ma$

$F = 0.5 \times 1100$

$F = 550 N$