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Deffense [45]
3 years ago
10

An object falls a distance h from rest. If it travels 0.460h in the last 1.00 s, find (a) the time and (b) the height of its fal

l.
Physics
2 answers:
nadya68 [22]3 years ago
7 0

Answer:

A. Time, t = 4.35s

B. Height of its fall, S = 92.72m

Explanation:

Vo = 0 m/s

Vi = 0.46h m/s

S = h m

a = 9.81 m/s2

To calculate the time taken, we need to get the value of the distance, h.

Using the equations of motion,

Vi^2 = Vo^2 + 2aS

Where Vi = final velocity

Vo = initial velocity

a = acceleration due to gravity

S = height of its fall

(0.46h)^2 = 0 + 2*9.81*h

0.2116h^2 = 19.62h

h = 19.62/0.1648

= 92.722 m

To calculate the time,

S = Vo*t +(1/2)*a*t^2

92.772 = 0 + (1/2)*9.81*t^2

t^2 = 185.44/9.81

= 18.904

t = sqrt(18.904)

= 4.348 s

svp [43]3 years ago
4 0

Answer:

a) t = 3.771s

b) h = 69.68 m

Explanation:

Given;

total distance covered = h

Using the second equation of motion;

h = ut + 0.5at² .....1

We know u=0, since the object fall from rest.

and also acceleration a = g (acceleration due to gravity)

The equation 1 becomes;

h = 0.5gt² .......2

Equation 2 is the overall equation of motion of the object.

Where;

h = height of fall

t = total time of fall

The motion have two phases.

1) distance travelled in the first phase is

h₁ = h - 0.46h = 0.54h

Time taken for the first phase is;

t₁ = t-1

2) distance travelled in the second phase is

h₂ = 0.46h

Time taken for second phase is

t₂ = 1.00s

Writing the equation of motion of the first phase where the object starts from rest, we have;

0.54h = 0.5g(t-1)² .....3

Substituting equation 2 into 3, we have;

0.54(0.5gt²) = 0.5g(t-1)²

divide both sides by 0.5g

0.54t² = (t-1)²

(t-1)² - 0.54t² = 0

Simplifying the equation above, we have;

t² - 2t +1 - 0.54t² = 0

Then we have a quadratic equation;

0.46t² - 2t +1 = 0

solving the quadratic equation, we have

t = 3.771 or t = 0.5764

Since t cannot be less than 1,

Recall that t₁ = t-1, and t₁ cannot be negative. so t>1

t = 3.771s

b) Using equation 2

h = 0.5gt²

h = 0.5×9.8×3.771²

h = 69.68 m

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a

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3 years ago
Kids are pelting a window with snowballs. On average, two snowballs of roughly 300-g mass hit the window each second, moving hor
hram777 [196]

Answer:

The average force exerted on the window due to two snowballs is 6 N

Explanation:

Given:

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For finding the average force,

Force is equal to the change in momentum,

   F = \frac{dP}{dt}

Here, final velocity is zero so we write,

 F = \frac{mv}{1}

Where dt = 1 sec

 F = 300 \times 10^{-30} \times 10

F = 3 N

Above value of force is due to one ball, but here given in question there are two ball,

F = 3 \times 2

F = 6 N

Therefore, the average force exerted on the window due to two snowballs is 6 N

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3 years ago
Two identical charges, 2 m apart, exert forces of magnitude 4 N on each other. The value of each charge is: 1. 9 × 105 C 2. 4.2
lesya692 [45]

Answer:

The value of each charge is 4.22 x 10⁻⁵ C

Explanation:

Given;

distance between the two identical charges, d = 2 m

the force of repulsion between these two charges, F = 4N

Apply Coulomb's law;

F = \frac{kq_1q_2}{r^2} \\\\but \ q_1 =q_2,then \ let \ q_1 =q_2 = q\\\\F = \frac{kq^2}{r^2}\\\\q^2 = \frac{Fr^2}{k}\\\\q^2 = \frac{4*2^2}{9*10^9} \\\\q ^2 = 1.7778*10^{-9}\\\\q = \sqrt{1.7778*10^{-9}}\\\\q =4.22 *10^{-5} C\\\\q= q_1=q_2= 4.22 *10^{-5} C

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7 0
3 years ago
Which term means the distance between two bridge supports?
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The best answer is b - span.

A span is the distance between two bridge supports The supports may be towers, columns, or even the wall of a canyon.

There are many kinds of bridges  but they all fall into three types namely beam, arch and suspension. The major difference between these three kinds of bridges is the distance that each can cross in  a single span.

For example, a modern beam bridge is likely to span a distance of 200 feet, a modern arch can span 800 or 1000feet,  and a modern suspension bridge can span up to 7000ft.


5 0
2 years ago
A family took a trip in a car traveling East from Greensboro to Wilmington, NC. Use the Graph to answer the questions below.
kotykmax [81]

Answer:

1). Average speed = 1.5 m per second

2). Average velocity = 1.5 m per second

Explanation:

1). Since, speed is a scalar quantity

   Therefore, average speed of the trip = \frac{\text{Total distance covered}}{\text{Total time taken}}

    From the graph attached,

   Total distance covered = 10 + 10 + 20 + 0 + 20 + 30

                                           = 90 meters

   Total time taken = 60 seconds

    Average speed = \frac{90}{60}

                               = 1.5 meter per second

2). Velocity is a vector quantity.

    Therefore, average velocity = \frac{\triangle d}{\triangle t}

                                                   = \frac{d_{60}-d_0}{60-0}

                                                   = \frac{90-0}{60-0}

                                                   = 1.5 meter per second                        

7 0
3 years ago
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