Parts of the eukaryotic cell worksheet answers
1 answer:
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1. The <span>conclusion that can be made about the results of your first cross between a homozygous red bull (RR) and a heterozygous red cow (Rr) is shown below :
You supposed to make a punnet square, so (picture)
</span>Than you will get that the first generation will be 50% homozygous dominant
and 50% heterozygous which lead us to conclusion :
<span>Crossing results in 50% (dominant homozygote) and 50% (dominant heterozygote).
</span>
2. Conclusion about the results of your second cross between a heterozygous red bull (Rr) and a heterozygous red cow (Rr) is shown in the second picture. And you can see that <span>in 25% (dominant homozygote), 50% (dominant heterozygote) and 25% (homozygous recessive).
3. Conclusion about </span>the results of your third cross between a homozygous white bull (rr) and a homozygous white cow (rr) are shown in the third picture. In this case you can see the result of <span> 100% (homozygous recessive).</span>
You supposed to make a punnet square, so (picture)
</span>Than you will get that the first generation will be 50% homozygous dominant
and 50% heterozygous which lead us to conclusion :
<span>Crossing results in 50% (dominant homozygote) and 50% (dominant heterozygote).
</span>
2. Conclusion about the results of your second cross between a heterozygous red bull (Rr) and a heterozygous red cow (Rr) is shown in the second picture. And you can see that <span>in 25% (dominant homozygote), 50% (dominant heterozygote) and 25% (homozygous recessive).
3. Conclusion about </span>the results of your third cross between a homozygous white bull (rr) and a homozygous white cow (rr) are shown in the third picture. In this case you can see the result of <span> 100% (homozygous recessive).</span>