Answer:
I would say b
<em>I might be wrong but I hope i helped! ^^</em>
<em></em>
<span>To have the disease, males need only one copy of the affected X.</span>
So, the frequency of affected males will be the frequency
of the disease allele = 0.02
Females must inherit two copies and be
homozygotes, so the frequency of affected females will be the double of frequency
of the disease allele = (0.02)
Since the ratio between female and male is 50:50
that is half of the population is male and half female
<span>Then the overall frequency of the disease will be,</span>
(0.5) (0.02) + (0.5) (0.0004) = 0.01 + 0.0002
<span>Thus, the frequency of affected
individuals in this population is <span>0.0102.</span></span>
Answer:
The phylum Hemichordata is the one that could form an evolutionary connection between the chordates and non-chordates.
Explanation:
To the phylum Hemichordata belongs a genus that scientists believe could explain how the chordates could evolve from the non-chordates. This genus is Balanoglossus, of the class Enteropneusta.
Balanoglossus is similar to a worm, whose habitat is the seabed, and like other hemicordates it has a stomach, a structure that forms part of its digestive system and fulfills the functions of a spine.
Learn more:
Chordates and non-chordates brainly.com/question/1387264
