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Anuta_ua [19.1K]
3 years ago
14

What is 0.4% of 750?

Mathematics
2 answers:
marusya05 [52]3 years ago
6 0

3 is 0.4% of 750. Honestly when you type the numbers into google it tells you sooo

elena55 [62]3 years ago
4 0
If you take 750x0.4%=
Your answer will be 3
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photoshop1234 [79]

Answer:

Pentagon and I think the area is 19.89 so if you round it, that will be 19.9

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What is the domain of the function below? {(0,2),(3,1),(5,2),(8,4)}
SCORPION-xisa [38]
They are all the x points on the graph like the range is the y
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Express 100,000 as a power of 10
Vedmedyk [2.9K]

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10^5

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7 0
2 years ago
What is the inverse function of 15x + 14
Hitman42 [59]
The inverse fraction of 15x+14 is f^-1 (x)= x/15-14/15
3 0
3 years ago
Find the average value of the function on the given interval.<br> f(x)=2 ln x; [1,e]
JulijaS [17]

Answer:

f_{avg}=\frac{1}{e-1}

Step-by-step explanation:

We are given that a function

f(x)=2lnx

We have to find the average value of function on the given interval [1,e]

Average value of function on interval [a,b] is given by

\frac{1}{b-a}\int_{a}^{b}f(x)dx

Using the formula

f_{avg}=\frac{1}{e-1}\int_{1}^{e}lnx dx

By Parts integration formula

\int(uv)dx=u\int vdx-\int(\frac{du}{dx}\int vdx)dx

u=ln x and v=dx

Apply by parts integration

f_{avg}=\frac{1}{e-1}([xlnx]^{e}_{1}-\int_{1}^{e}(\frac{1}{x}\times xdx))

f_{avg}=\frac{1}{e-1}(elne-ln1-[x]^{e}_{1})

f_{avg}=\frac{1}{e-1}(e-0-e+1)=\frac{1}{e-1}

By using property lne=1,ln 1=0

f_{avg}=\frac{1}{e-1}

8 0
2 years ago
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