Answer:
The correct answer is option 3.
Explanation:
2A → B + C
First trial ;
[A] = x , Rate of the reaction = R
Rate law of the reaction can be written as:
..[1]
Second trial ;
[A] = 3x , Rate of the reaction = R' = 9R
Rate law of the reaction can be written as:
![R'=k[3x]^a](https://tex.z-dn.net/?f=R%27%3Dk%5B3x%5D%5Ea)
..[2]
[1] ÷ [2]
![\frac{R}{9R}=\frac{k[x]^a}{k[3x]^a}](https://tex.z-dn.net/?f=%5Cfrac%7BR%7D%7B9R%7D%3D%5Cfrac%7Bk%5Bx%5D%5Ea%7D%7Bk%5B3x%5D%5Ea%7D)
a = 2
Rate of the reaction : ![R=k[A]^3](https://tex.z-dn.net/?f=R%3Dk%5BA%5D%5E3)
The order of the reaction is 2. This is because in the rate law expression the the power of the concentration of reactant A id 2.
Chloroplasts is an important part in the process of photosynthesis in some organisms. The chloroplast absorbs the energy in sunlight and uses it to produce sugars.
The pH of the solution is 3,76
Why?
To solve this problem we have to apply the Henderson-Hasselbach equation, which is used whenever we need to calculate the pH of a solution of an acid HA (Lactic Acid) and its conjugate base A⁻ (Sodium Lactate)
We can use either moles or concentrations for this equation. In this case, we are going to use the moles, and we are going to take the pKa of lactic acid as 3,86:

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Since you did not give the reactions, i cannot give the answers.
In organic and inorganic chemistry, nucleophilic substitution is a fundamental class of reactions in which an electron rich nucleophile selectively bonds with or attacks the positive or partially positive (+ve)charge of an atom or a group of atoms to replace a leaving group; the positive or partially positive atom is referred to as an electrophile. The whole molecular entity of which the electrophile and the leaving group are part is usually called the substrate.
The most general form for the reaction may be given as the following:
<span>Nuc: + R-LG → R-Nuc + LG<span>:</span></span>
I think it is B, but i am not sure