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Angelina_Jolie [31]
3 years ago
13

I need help with this ASAP.

Chemistry
1 answer:
adelina 88 [10]3 years ago
3 0

Answer:

bob

Explanation:

owa owa owa

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The graph shows the reaction pathway for the reaction Q + R N + M. Interpret the graph by describing what each of the letters (A
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Answer: The reaction is exothermic reaction as the energy of products is less than the energy of reactants.

Explanation: Exothermic reactions are defined as the reactions in which energy of the product is less than the energy of the reactants. The total energy is released in the form of heat and \Delta H for the reaction comes out to be negative.

Labeling of the parts in the diagram:

A represents the activation energy which is the energy required by reactants to cross the energy barrier to get converted to products.

E represents the potential energy of the reactants.

B represents the activated complex.

D represents the potential energy of the products.

C represents the total enthalpy change of the reaction, which comes out to be negative for exothermic reactions.

\Delta H=E_P-E_R

7 0
3 years ago
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please help me with Chem I ONLY HAVE 5 MINUTES if methane gas (CH4) flows at a rate of 0.25L/s, how many grams of methane gas wi
Nookie1986 [14]

Answer:

643g of methane will there be in the room

Explanation:

To solve this question we must, as first, find the volume of methane after 1h = 3600s. With the volume we can find the moles of methane using PV = nRT -<em>Assuming STP-</em>. With the moles and the molar mass of methane (16g/mol) we can find the mass of methane gas after 1 hour as follows:

<em>Volume Methane:</em>

3600s * (0.25L / s) = 900L Methane

<em>Moles methane:</em>

PV = nRT; PV / RT = n

<em>Where P = 1atm at STP, V is volume = 900L; R is gas constant = 0.082atmL/molK; T is absolute temperature = 273.15K at sTP</em>

Replacing:

PV / RT = n

1atm*900L / 0.082atmL/molK*273.15 = n

n = 40.18mol methane

<em>Mass methane:</em>

40.18 moles * (16g/mol) =

<h3>643g of methane will there be in the room</h3>
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3 years ago
Help on science please
Otrada [13]

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A gas is enclosed in a cylinder fitted with a piston. The volume of the gas is 2.00 L at 0.524 atm. The piston is moved to incre
MAXImum [283]

Answer:0.20L

Explanation:

Data

P1 =0.524atm

V1=2L

P2=5.15atm

V2=?

Apply Boyle' law

P1V1 =P2V2

P2 =P1V1/P2

= 0.524x 2 /5.15

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