D. the activation energy is the displacement of energy needed for the reaction, so the distance underneath the maximum point
Answer:
18.94%.
Explanation:
- The decay of carbon-14 is a first order reaction.
- The rate constant of the reaction (k) in a first order reaction = ln (2)/half-life = 0.693/(5730 year) = 1.21 x 10⁻⁴ year⁻¹.
- The integration law of a first order reaction is:
<em>kt = ln [A₀]/[A]</em>
k is the rate constant = 1.21 x 10⁻⁴ year⁻¹.
t is the time = 13,750 years.
[A₀] is the initial percentage of carbon-14 = 100.0 %.
[A] is the remaining percentage of carbon-14 = ??? %.
∵ kt = ln [Ao]/[A]
∴ (1.21 x 10⁻⁴ year⁻¹)(13,750 years) = ln (100.0%)/[A]
1.664 = ln (100.0%)/[A]
Taking exponential for both sides:
5.279 = (100.0%)/[A]
<em>∴ [A]</em> = (100.0%)/5.279 = <em>18.94%.</em>
Answer:
CH3COO-
Explanation:
The conjugate base if a weak acid is a strong base, and the conjugate base of a strong acid is a weak base.
Acetic acid is a weak acid, so its conjugate base (CH3COO-) is a strong base.
Nitric, sulfuric, and hydrochloric acids are all strong acid. Their conjugate bases (NO3-, SO4^2-, and Cl- are all weak bases.
The answer is A
Trust. Me
I have got no idea how to answer this question sorry
