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Vitek1552 [10]
2 years ago
5

Calculate the volume(mo) of 0.50 M NaCl stock solution need to make 100mL of a diluted solution with a concentration of 0.03

Chemistry
1 answer:
Svetach [21]2 years ago
5 0

Answer:

.006L or 6 mL

Explanation:

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Describe how you could use two LB/agar plates, some E. coli, and some ampicillin to determine how E. coli cells are affected by
KiRa [710]

Answer:

For this experiment we are going to take plate 1 as the control plate, so, in it there will be just E. coli in LB/agar; in plate 2, we are going to put E. coli in LB/agar and some ampicillin.  Then, we have to wait for the E. coli colonies to form. After a while, the E. coli growth can be compared on both plates and determine if ampicillin affects or not the E. coli colonies.

Explanation:

If the ampicillin affects negatively E. coli colonies, we are going to observe that in plate 1 (control plate) there are E. coli colonies growing, but in plate 2, there is no E. coli colonies or, at least, there is a fewer number of colonies on it. If ampicillin doesn't affect E.coli, plate 1 (control) and plate 2 (ampicillin experiment) are going to be similar in number of colonies.

8 0
3 years ago
9. A student observed the following reaction:
Gelneren [198K]

Answer:

The substance that remained on the filter paper is Al(OH).

Explanation:

  • Filter paper is the substance that is used in laboratory to separate the solid objects. It doesn't filter aqueous and gaseous products.
  • So in our experiment the product formed is aluminum hydroxide Al(OH)   and sodium chloride (NaCl).
  • Between two products, sodium chloride is in aqueous form as indicated in the question. So it wont remain in the filter paper.
  • Hence aluminum hydroxide being only solid product remains on the filter paper.
8 0
3 years ago
Please help me! 45 points each!!
Sveta_85 [38]

Answer:

CH4+ 2Cl2→CH2Cl2+ 2HCl

Explanation:

mass is 132.8`125

as methane and dichlormethane has the same molar ration 1 to 1

mol of ch4 is 1.5625

so 1.5625 times mr of ch2cl2 is 132.8125

8 0
3 years ago
The concentration of calcium in a cell is 0.3%. The concentration of calcium in the surrounding fluid is 0.1%. How could the cel
iragen [17]

Answer:

Primary active transport                                                                                              

Explanation:

In a cell, the movement of molecules like calcium ions (Ca²⁺), <em>to a region having high solute concentration from a region having low solute concentration, through the cell membrane requires metabolic energy</em> and is known as Primary active transport.

It is given that the concentration of calcium in the cell (0.3%) is greater than the concentration of calcium in the fluid surrounding the cell (0.1%). <em><u>So the calcium ions move into the cell and the cell obtains more calcium. </u></em>

<u>Therefore, the cell obtains more calcium by the process of Primary active transport.</u>

4 0
4 years ago
Consider the following reaction: 2 Bi(s) + 3 Cl2(g) → 2 BiCl3(s)
Mandarinka [93]

Taking into account the reaction stoichiometry, 1.119 grams of chlorine gas are required to produce 3.32 grams of bismuth chloride is produced.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

2 Bi + 3 Cl₂ → 2 BiCl₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • Bi: 2 moles
  • Cl₂: 3 moles
  • BiCl₃: 2 moles

The molar mass of the compounds is:

  • Bi: 209 g/mole
  • Cl₂: 70.90 g/mole
  • BiCl₃: 315.45 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

Bi: 2 moles ×209 g/mole=418  g

Cl₂: 3 moles ×70.90 g/mole= 212.7 g

BiCl₃: 2 moles ×315.45 g/mole= 630.9 g

<h3>Mass of Cl₂ required</h3>

The following rule of three can be applied: If by reaction stoichiometry 630.9 grams of BiCl₃ are formed by 212.7 grams of Cl₂, 3.32 grams of BiCl₃ are formed by how much mass of Cl₂?

mass of Cl_{2} =\frac{3.32 grams of BiCl_{3}x212.7 grams of Cl_{2} }{630.9 grams of BiCl_{3}}

<u><em>mass of Cl₂= 1.119 grams</em></u>

Finally, 1.119 grams of chlorine gas are required to produce 3.32 grams of bismuth chloride is produced.

Learn more about the reaction stoichiometry:

<u>brainly.com/question/24741074</u>

<u>brainly.com/question/24653699</u>

5 0
2 years ago
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