Option c) 1.5 V
Explanation:
<em>As the circuit is build in series first we will find the current passing through the complete circuit. Current stays the same in each element is the series cirucuit, however, the voltage is different.</em>
Voltage is given by the following formula:
V = IR
<em>Because we have to find current through whole circuit, we will first find resistance of the whole circuit.</em>
Equivalent Resistance R(eq): R1 + R2 = 60 + 60 = 120 ohm
Current passing through whole circuit be:
= 0.025
Now we will find out the voltage between C and D:
Current stays the same in series circuit: I = 0.025 c
Resistance between C and D is, R = 60 ohm
Voltage becomes, V = IR = 0.025 * 60 = 1.5 V
Answer:
In general solids are easier to transport than liquids, but the above metal example is a valid one and the only other one that comes to mind is that of concrete. It is mixed as a liquid and transported as such, but then sprayed or laid down to dry and form a solid surface or filler.
Explanation:
Answer:
her displacement <em>s=337.5m</em>
Explanation:
check out the above attachment ☝️
The average speed is 116.66m/s.
Given - The path traced is 14km , time for jogging is 2 hrs=120min
To find the average speed-
- Speed refers to the ease of the movement and degree of mobility as a result of force application.
- Due to this there is involvement of velocity.
- Journey of average speed is the cumulative of distances and time.
- Kinetic theory refers to the Boltzmann constant connecting to the standards of distance traversed.
calculations-
Speed= 14 000 / 120
= 116.66m/s
To learn more about average speed -
<u>brainly.com/question/27753148</u>
#SPJ4
Answer:
Explanation:
Initial height from the ground = .41 m
Final height = 1m
Height by which Kelli was raised ( h )= .59 m
When she passes through the lowest point , she loses P E
= mgh
= 440 x .59
= 259.6 J
kinetic energy possessed by her
= 1/2 mv²
= .5 x (440/9.8) x 2²
= 89.8 J
Difference of energy is lost due to work by air friction
work done by friction = 89.8 - 259.6
= - 169.8 J