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2 years ago

What is the product of the complex numbers (3 + i) and (3 - i)?

Mathematics

1 answer:

dedylja [7]2 years ago

5 0

Answer:

\left(3+i\right)y\left(3-i\right)=10y

Step-by-step explanation:

\left(3+i\right)y\left(3-i\right)

\left(3+i\right)\left(3-i\right)y

=y\cdot \:10

=10y

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The number of decimal places in the product will be sum of the factor"s decimal place.So the product will have 1,2,3 or 4 decima

vampirchik [111]

Answer:

$0.47 \to 2\ digits$

$3.2 \to 1\ digit$

$Product \to 3\ digits$

Step-by-step explanation:

Given

$0.47 * 3.2 =$

See comment for complete question

Required

The number of decimal places

To do this, we simply calculate the number of digits after the decimal points

$0.47 \to 2\ digits$

$3.2 \to 1\ digit$

The product is the sum of the digits above 2 + 1 = 3

Hence:

$Product \to 3\ digits$

6 0

3 years ago

John and Martha are contemplating having children, but John’s brother has galactosemia (an autosomal recessive disease) and Mart

Rina8888 [55]

<h2>Answer:</h2>

$Probability=\frac{1}{24}$

<h2>Step-by-step explanation:</h2>

As the question states,

John's brother has Galactosemia which states that his parents were both the carriers.

Therefore, the chances for the John to have the disease is = 2/3

Now,

Martha's great-grandmother also had the disease that means her children definitely carried the disease means probability of 1.

Now, one of those children married with a person.

So,

Probability for the child to have disease will be = 1/2

Now, again the child's child (Martha) probability for having the disease is = 1/2.

Therefore,

<u>The total probability for Martha's first child to be diagnosed with Galactosemia will be,</u>

$Probability=\frac{2}{3}\times \frac{1}{2}\times \frac{1}{2}\times \frac{1}{4}\\Probability=\frac{1}{24}$

(Here, we assumed that the child has the disease therefore, the probability was taken to be = 1/4.)

<em><u>Hence, the probability for the first child to have Galactosemia is $\frac{1}{24}$ </u></em>

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3 years ago

Use power series to solve (x + 1)y' + 3y = 0

enyata [817]

X= -4 for solving x and y= 0 for solving y

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2 years ago

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Brums [2.3K]

Answer:

m = E/c²

Step-by-step explanation:

E = mc²

mc² = E

Divide both sides by c².

m = E/c²

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1 year ago

Convert 75 seconds to hours<br>

ZanzabumX [31]

It is 0.02083333 hours.

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2 years ago