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LenKa [72]
4 years ago
12

Gabriel wants to make five banners for the parade. He has 75 feet of material. The size of four of the banners are: 12 1/3 ft.,

16 1/6 ft., 11 3/4 ft., and 14 1/2 ft. How much material is left for the fifth banner?
Mathematics
1 answer:
n200080 [17]4 years ago
8 0

Answer:

  20 1/4 ft

Step-by-step explanation:

Subtracting the four given lengths from 75 feet will tell you how much is left.

  75 - (12 1/3 +16 1/6 +11 3/4 +14 1/2) = 75 -54 3/4 = 20 1/4

Gabriel has 20 1/4 ft of material left for his 5th banner.

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Answer:

$35,000

Step-by-step explanation:

The computation of the dividend amount is given below:

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where,

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Now

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4 0
3 years ago
A. 5 cartoons/toy<br> B. 12 toys/ cartoon<br> C. 5 toys/ cartoon
Alla [95]

Answer:

c

Step-by-step explanation:

8 0
3 years ago
14.1-191<br> Is this the answer?
enyata [817]
I don’t know if this is what you’re asking but 14.1-191 = -176.9
4 0
3 years ago
Read 2 more answers
Rearrange the equation so u is the independent variable.<br><br> 4u+8w=-3u+2w4u+8w=−3u+2w
stiv31 [10]

Answer:

Step-by-step explanation:

4u + 8v = -3u + 2v

Solving 4u + 8v = -3u + 2v

Solving for variable 'u'.

Move all terms containing u to the left, all other terms to the right.

Add '3u' to each side of the equation. 4u + 3u + 8v = -3u + 3u + 2v

Combine like terms: 4u + 3u = 7u 7u + 8v = -3u + 3u + 2v

Combine like terms: -3u + 3u = 0 7u + 8v = 0 + 2v 7u + 8v = 2v

Add '-8v' to each side of the equation. 7u + 8v + -8v = 2v + -8v

Combine like terms: 8v + -8v = 0 7u + 0 = 2v + -8v 7u = 2v + -8v

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7 0
3 years ago
Jeffrey is using a copy machine to make posters for a school play. The machine prints the posters at a constant rate. After 3 mi
jasenka [17]

Answer:

B: 11 minutes.

Step-by-step explanation:

So, we know that the machine prints at a constant rate.

After 3 minutes, the machine prints 108 posters.

So, let’s find the <em>unit rate. </em>We will divide the output over the input. So:

108\text{ posters}/3\text{ minutes}=36\text{ posters/min}

So, the unit rate of the machine is 36 posters per minute.

We can write an equation. If t represent the number of minutes and p represent the amount of posters, then:

p=36t

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We want to know how long it will take Jeffrey to make 396 posters.

So, we can substitute 396 for p and solve for t. Hence:

396=36t

Divide both sides by 36:

t=11

Therefore, it will take Jeffrey 11 minutes to make 396 posters.

7 0
3 years ago
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