What is the answer to this question?
1 answer:
Lets start by factoring the 216 into its smaller parts.
![\sqrt[3]{2 * 2 * 2 * 3 * 3 * 3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2%20%2A%202%20%2A%202%20%2A%203%20%2A%203%20%2A%203%7D)
From here, we can separate the three 2s and the three 3s into two separate radicals.
![\sqrt[3]{2*2*2} * \sqrt[3]{3*3*3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2%2A2%2A2%7D%20%2A%20%20%5Csqrt%5B3%5D%7B3%2A3%2A3%7D%20)
Since we have three copies of the same number in each, the answer to the cube root is the number we have the copies of.
![\sqrt[3]{2*2*2} * \sqrt[3]{3*3*3} = 2 * 3](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B2%2A2%2A2%7D%20%2A%20%20%5Csqrt%5B3%5D%7B3%2A3%2A3%7D%20%3D%202%20%2A%203)
Finally, we just need to multiply out what remains to find the solution.
So, the final answer is 6.
From here, we can separate the three 2s and the three 3s into two separate radicals.
Since we have three copies of the same number in each, the answer to the cube root is the number we have the copies of.
Finally, we just need to multiply out what remains to find the solution.
So, the final answer is 6.
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as you notice above, is the first-row components from A, multiplying all the columns subsequently on B, and you add the products of that row, that gives you one component on the AB matrix
in the one above, we end up with a 2x3 AB matrix
Answer:
B) Angle 5 and angle 4
Step-by-step explanation:
Given
See attachment for sketch
See comment for options
Required
The alternate interior angles
Interior angles are such that they are located between the given parallel lines.
In the attached sketch, the interior angles are: 3, 4, 5 and 6
Alternate angles are at the opposite sides of the transversal
Hence:
<em>4 and 5 are alternate interior</em>
<em>3 and 5 are also alternate interior</em>
