What is the answer to this question?
1 answer:
Lets start by factoring the 216 into its smaller parts.
![\sqrt[3]{2 * 2 * 2 * 3 * 3 * 3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2%20%2A%202%20%2A%202%20%2A%203%20%2A%203%20%2A%203%7D)
From here, we can separate the three 2s and the three 3s into two separate radicals.
![\sqrt[3]{2*2*2} * \sqrt[3]{3*3*3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2%2A2%2A2%7D%20%2A%20%20%5Csqrt%5B3%5D%7B3%2A3%2A3%7D%20)
Since we have three copies of the same number in each, the answer to the cube root is the number we have the copies of.
![\sqrt[3]{2*2*2} * \sqrt[3]{3*3*3} = 2 * 3](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B2%2A2%2A2%7D%20%2A%20%20%5Csqrt%5B3%5D%7B3%2A3%2A3%7D%20%3D%202%20%2A%203)
Finally, we just need to multiply out what remains to find the solution.
So, the final answer is 6.
From here, we can separate the three 2s and the three 3s into two separate radicals.
Since we have three copies of the same number in each, the answer to the cube root is the number we have the copies of.
Finally, we just need to multiply out what remains to find the solution.
So, the final answer is 6.
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To solve the problem we could separate the figure into three parts. First figure is a triangle, second figure is a rectangle, third figure is a triangle. See image attached.
Solve each area of the figures
First figure, a triangle that have 7 units long of the base, and 2 units long of the height.
a = 1/2 × b × h
a = 1/2 × 7 × 2
a = 14/2
a = 7
The area of the first figure is 7 units²
Second figure is a rectangle, the length of the rectangle is 7 units, the width of the rectangle is 4 units.
a = l × w
a = 7 × 4
a = 28
The area of the second figure is 28 units²
Third figure is a triangle, the base is 7 units long and the height is 2 units long.
a = 1/2 × b × h
a = 1/2 × 7 × 2
a = 14/2
a = 7
The area of the third figure is 7 units²
The area of the three figures
area = first figure area + second figure area + third figure area
area = 7 + 28 + 7
area = 42
The total area of the figures is 42 units²
Solve each area of the figures
First figure, a triangle that have 7 units long of the base, and 2 units long of the height.
a = 1/2 × b × h
a = 1/2 × 7 × 2
a = 14/2
a = 7
The area of the first figure is 7 units²
Second figure is a rectangle, the length of the rectangle is 7 units, the width of the rectangle is 4 units.
a = l × w
a = 7 × 4
a = 28
The area of the second figure is 28 units²
Third figure is a triangle, the base is 7 units long and the height is 2 units long.
a = 1/2 × b × h
a = 1/2 × 7 × 2
a = 14/2
a = 7
The area of the third figure is 7 units²
The area of the three figures
area = first figure area + second figure area + third figure area
area = 7 + 28 + 7
area = 42
The total area of the figures is 42 units²