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photoshop1234 [79]
3 years ago
14

A manufacturer ships its product in boxes with

Mathematics
2 answers:
Alla [95]3 years ago
7 0
3 would be the volume  hopes this is good 
AfilCa [17]3 years ago
4 0
3 btw hopes that help
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A principal of $4,570 is placed in an account that earns 4. 5% interest. If the interest is compounded annually, how much money
iVinArrow [24]

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$4570\\ r=rate\to 4.5\%\to \frac{4.5}{100}\dotfill &0.045\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &5 \end{cases} \\\\\\ A=4570\left(1+\frac{0.045}{1}\right)^{1\cdot 5}\implies A=4570(1.045)^5\implies A\approx 5695.05

8 0
3 years ago
Need answers for Question 8 and 9
Advocard [28]

number 8 is C i think

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3 years ago
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lisa goes to school for 7 hours per day works 3 hours per day and sleeps 8 hours per day. what is the ratio of hours lisa works
frozen [14]

Answer:

ratio of hours lisa works to hours lisa sleeps= 3:8

Step-by-step explanation:

lisa goes to school for 7 hours per day lisa works 3 hours per day

Lisa sleeps 8 hours per day.

For the ratio of hours lisa works to hours lisa sleeps

ratio of hours lisa works to hours lisa sleeps= hours Lisa works/hours Lisa sleeps

ratio of hours lisa works to hours lisa sleeps= 3/8

ratio of hours lisa works to hours lisa sleeps= 3:8

4 0
3 years ago
In the diagram, AABC ~ ADEF. Find the value of x.
Andrew [12]

Answer:

B

Step-by-step explanation:

bdeehvdvjwjkwkwwjehheeh

If you dont know the anwser its always B

3 0
2 years ago
How do properties of integer exponents help you write equivalent expressions
olga55 [171]

When writing equivalent expressions, there are often several possible orders in which to simplify them. However, they will all take you to the same result as long as you do not make a mistake when using the properties. In this example, you will distribute the outer exponent first using the Power of a Product Property.

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3 years ago
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