Answer:
got here just in time phew :3
Step-by-step explanation:
Imaginary numbers are not rational which may lead you to believe that they must be irrational. Though logical, you would still be incorrect because “irrational” also applies only to real numbers.
Step-by-step explanation:
Pythagoras Theorem:
hipotenuse²=leg₁²+leg₂²
First posible triangle:
hypotenuse=13 (13²=169)
leg₁=12 ( 12²=144)
leg₂=5 (5²=25)
13³=144 + 25
Answer:can be side lengths of a triangle
Second triangle:
hypotenuse=12.6 (12.6²=158.76)
leg₁=6.7 ( 6.7²=44.89)
leg₂=6.5 (6.5²=42.25)
leg₁²+leg₂²=44.89+42.25=87.14≠158.76
Answer: cannot be side lenghts of a triangle.
third triangle:
hypotenuse=13 (13²=169)
leg₁=12 ( 12²=144)
leg₂=11 (11²=121)
leg₁²+leg₂²=144+121=265≠169
Answer: cannot be side lenghts of a triangle.
fourth triangle:
hypotenuse=13 (13²=169)
leg₁=6 ( 6²=36)
leg₂=4 (4²=16)
leg₁²+leg₁²=36+16=52≠169
Answer: cannot be side lenghts of a triangle.
Answer:
4 seconds
Step-by-step explanation:
When the ball is on the ground h = 0, hence
- 16t² + 64t = 0 ( solve for t )
factor out - 16t
- 16t(t - 4) = 0
equate each factor to zero and solve for t
- 16t = 0 ⇒ t = 0
t - 4 = 0 ⇒ t = 4
the 0 solution is the height of the ball before being hit and
the time the ball takes to hit the ground is 4 seconds
<span>B.) It is a straight line joining the points (0, −2), (2, 1), and (−2, −5).
[ It is because x- & y-coordinates are valid in this situation ]
Hope this helps!</span>
