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Sergio [31]
3 years ago
14

Gold (111) Chloride

Chemistry
1 answer:
ZanzabumX [31]3 years ago
4 0

Answer:

Explanation:

Gold (111) Chloride:

AuCl₃

The oxidation state of gold is +3.

Chlorine is present in group seventeen and have seven valance electrons . Thus it accept one electron to complete the octet and show oxidation state -1.

When it react with gold(III) three chlorine atoms are combine with one gold atom to make compound overall neutral.

Calcium Carbonate:

CaCO₃

Carbonate formula is CO₃²⁻ . It means it carry -2 charge . Calcium is present in group two. It has two valance electrons and lose them to get complete octet thus shows +2 oxidation state.

When it combine with carbonate the overall compound is neutral because -2 and +2 charges cancel each other.

Hydrobromic Acid

HBr

Hydrogen has one electron while bromine has seven valance electrons. Bromine require one more electron to complete the octet. It react with hydrogen by sharing of one electron of hydrogen and form polar covalent compound.

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Which has the higher percentage of aluminum, Al2O, or Al(NO3)3
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Al₂O  has a higher percentage of aluminium.

Explanation:

To solve this problem, we have to compare the molar mass of the aluminium in each compound to one another as percentage of the whole compound:

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Percentage by mass of Al in Al₂O = \frac{2x27}{70} x 100 = 77%

Percentage by mass of Al in  Al(NO₃)₃ = \frac{27}{213} x 100 = 12.7%

Al₂O  has a higher percentage of aluminium.

learn more:

Molar mass brainly.com/question/2861244

#learnwithBrainly

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How many carbon atoms are represented in the formula for CaMg3(CO3)4​
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Oxidation number of au in kaucl4
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hope this helps!

3 0
3 years ago
Read 2 more answers
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