Answer:
THE MASS OF NITROGEN GAS IN THIS CONDITIONS IS 0.0589 g
Explanation:
In an ideal condition
PV = nRT or PV = MRT/ MM where:
M = mass = unknown
MM =molar mass = 28 g/mol
P = pressure = 2 atm
V = volume = 25 mL = 0.025 L
R = gas constant = 0.082 L atm/mol K
T = temperature = 290 K
n = number of moles
The gas in the question is nitrogen gas
Molar mass of nitrogen gas = 14 * 2 = 28 g/mol
Then equating the variables and solving for M, we have
M = PV MM/ RT
M = 2 * 0.025 * 28 / 0.082 * 290
M = 1.4 / 23.78
M = 0.0589 g
The mass of the nitrogen gas at ideal conditions of 2 atm, 25 mL volume and 290 K temperature is 0.0589 g
<h3>
Answer:</h3>
134 atm
<h3>
Explanation:</h3>
- Based on the pressure law, the pressure of a gas varies directly proportionally to the absolute temperature at a constant volume.
- Therefore; we are going to use the equation;

In this case;
Initial pressure, P1 = 144 atm
Initial temperature, T1 (48°C) = 321 K
Final temperature, T2 (25°C) = 298 K
We need to find the final pressure,
Therefore;
P2 = (P1/T1)T2
= (144/321)× 298 K
= 133.68 atm
= 134 atm
Therefore, the new pressure will be 134 atm.
The molar mass of copper is 63.55 g/mol. So, you convert grams to moles 127.08/63.55 =1.999 moles copper. Now, 1 mole = 6.022e23 atoms, so multiply # of moles by 6.022e23. 1.999 x 6.022e23= # of atoms of copper.
V (speed) = f (frequency) * y (meant to be lambda) (wavelength)
y = v/f (v is speed of light --3.0*10^8m/s)
y = 3.0*10^8/1.5*10^13
The answer is y = 2.0*10-5.
The change in enthalpy shows on the graph is the red arrow shows that enthalpy is positive, indicating an endothermic reaction.
<h3>What is potential energy?</h3>
Energy is the basic thing to do any reaction or any process. There are many kinds of energy are present that are use indifferent processes.
Potential energy is the energy that is saved to do a work, or the energy that is present before a work occurred.
The graph is attaches below.
Thus, the correct option is A. The red arrow shows that enthalpy is positive, indicating an endothermic reaction.
Learn more about potential energy
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