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Pie
3 years ago
5

Explain how RNA polymerase recognizes where transcription should begin. Describe the promoter, the terminator, and the transcrip

tion unit.
Biology
1 answer:
Sever21 [200]3 years ago
7 0

Answer:

Explanation:

Transcription is the process by which a DNA nucleotide sequence is used as a template for the synthesis of an RNA molecule, which can be mRNA, tRNA or rRNA, by means of the enzyme RNA dependent DNA polymerase. Transcription in prokaryotes and eukaryotes differs in several respects, so they are studied separately.

1. The precursors of RNA synthesis are the four ribonucleotides 5 ’triphosphates (adenosine 5’-triphosphate, guanosine 5’-triphosphate, cytosine 5’-triphosphate and uridine 5’-triphosphate).

2. In the condensation reaction between the 5 'trisphosphate group of the incoming nucleotide and the 3'-OH group of the last nucleotide in the chain, the incoming nucleotide loses its two terminal phosphate groups. Its α group is used in the phosphodiester bond that binds it to the chain. This reaction occurs at the polymerase catalytic site.

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What is NOT a characteristic of saturated fats
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Answer:

A) Fats provide 12 kcals of energy per gram.

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suggest TWO reasons why fewer birds and other small animals can survive in the areas left after trees have been cut down​
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Answer:

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Describe the substrate specificity of chymotrypsin and the structural feature that determines this specificity.
serg [7]

Answer:

The main substrate of chymotrypsin includes tryptophan, tyrosine, phenylalanine and methionine

Explanation:

1.

Histidine yields a proton to aspartate and recovers it from serine.

Seen in another way: aspartate captures a proton from the serine through histidine.

2.

a) The serine (deprotonated) is thus capable of attacking the peptide bond (nucleophilic carbonyl attack) and forms a tetrahedral intermediate; The substrate is thus covalently bound to the enzyme (now it is a transition state).

b) The peptide bond is broken and the released amino terminus (R) recovers a proton from histidine.

c) Histidine, in turn, recovers it from aspartic.

3.

a) Aspartate captures a proton of histidine again, so that it can capture it in turn from water.

b) This generates a hydroxide anion that attacks the ester intermediate between the serine and the carboxyl part (R ′) of the substrate peptide.

c) A new tetrahedral intermediate bound to the enzyme is formed (via serine residue).

4.

a) The carboxyl group of the peptide is regenerated, the serine being separated and the other peptide fragment being free (the R ′ part with a free carboxyl end)

b) The serine recovers the proton at the expense of histidine, which in turn captures it from aspartic acid.

c) The catalytic triad (Asp, His, Ser) has been regenerated in its original state.

The net reaction is:

R–NH – CO –R ′ + H2O ⟶ R– NH2 + HOOC –R ′ ⟶ R – NH3 + + −OOC –R ′

The active site or catalytic center of chymotrypsin is formed by several amino acid residues, among which the essential role corresponds to the "catalytic triad".

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3 years ago
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Answer:

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