1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
KatRina [158]
3 years ago
13

There are three grades in the school. One grade has 1/3 of the students, one grade has 1/4 of the students. What fraction of stu

dents is in the remaining grade?
Mathematics
1 answer:
AlladinOne [14]3 years ago
4 0

Answer:

Step-by-step explanation:

Let x represent the total number of stdents that has all grades in the school.

There are three grades in the school. One grade has 1/3 of the students, this means that number of students that belongs tho this grade is 1/3 × x = x/3

One grade has 1/4 of the students, this means that number of students that belongs to this grade is 1/4 × x = x/4

Total number of students in both grades would be x/3 +/x/4 = 7x/12

The number of students in the remaining grade would be

x - 7x/12 = 5x/12

fraction of students in the remaining grade would be

(5x/12)/x = 5/12

You might be interested in
HELP mE need math help 20 points no links or imma report HeLP mE
Lapatulllka [165]

Answer:

A - is the best answer...

4 0
2 years ago
Three students from Milton Middle School are running for class president. A preliminary poll was taken in three homeroom classes
xxTIMURxx [149]
Your answer is ian because he has the most votes 


 
5 0
3 years ago
Read 2 more answers
The lifetime X (in hundreds of hours) of a certain type of vacuum tube has a Weibull distribution with parameters α = 2 and β =
stich3 [128]

I'm assuming \alpha is the shape parameter and \beta is the scale parameter. Then the PDF is

f_X(x)=\begin{cases}\dfrac29xe^{-x^2/9}&\text{for }x\ge0\\\\0&\text{otherwise}\end{cases}

a. The expectation is

E[X]=\displaystyle\int_{-\infty}^\infty xf_X(x)\,\mathrm dx=\frac29\int_0^\infty x^2e^{-x^2/9}\,\mathrm dx

To compute this integral, recall the definition of the Gamma function,

\Gamma(x)=\displaystyle\int_0^\infty t^{x-1}e^{-t}\,\mathrm dt

For this particular integral, first integrate by parts, taking

u=x\implies\mathrm du=\mathrm dx

\mathrm dv=xe^{-x^2/9}\,\mathrm dx\implies v=-\dfrac92e^{-x^2/9}

E[X]=\displaystyle-xe^{-x^2/9}\bigg|_0^\infty+\int_0^\infty e^{-x^2/9}\,\mathrm x

E[X]=\displaystyle\int_0^\infty e^{-x^2/9}\,\mathrm dx

Substitute x=3y^{1/2}, so that \mathrm dx=\dfrac32y^{-1/2}\,\mathrm dy:

E[X]=\displaystyle\frac32\int_0^\infty y^{-1/2}e^{-y}\,\mathrm dy

\boxed{E[X]=\dfrac32\Gamma\left(\dfrac12\right)=\dfrac{3\sqrt\pi}2\approx2.659}

The variance is

\mathrm{Var}[X]=E[(X-E[X])^2]=E[X^2-2XE[X]+E[X]^2]=E[X^2]-E[X]^2

The second moment is

E[X^2]=\displaystyle\int_{-\infty}^\infty x^2f_X(x)\,\mathrm dx=\frac29\int_0^\infty x^3e^{-x^2/9}\,\mathrm dx

Integrate by parts, taking

u=x^2\implies\mathrm du=2x\,\mathrm dx

\mathrm dv=xe^{-x^2/9}\,\mathrm dx\implies v=-\dfrac92e^{-x^2/9}

E[X^2]=\displaystyle-x^2e^{-x^2/9}\bigg|_0^\infty+2\int_0^\infty xe^{-x^2/9}\,\mathrm dx

E[X^2]=\displaystyle2\int_0^\infty xe^{-x^2/9}\,\mathrm dx

Substitute x=3y^{1/2} again to get

E[X^2]=\displaystyle9\int_0^\infty e^{-y}\,\mathrm dy=9

Then the variance is

\mathrm{Var}[X]=9-E[X]^2

\boxed{\mathrm{Var}[X]=9-\dfrac94\pi\approx1.931}

b. The probability that X\le3 is

P(X\le 3)=\displaystyle\int_{-\infty}^3f_X(x)\,\mathrm dx=\frac29\int_0^3xe^{-x^2/9}\,\mathrm dx

which can be handled with the same substitution used in part (a). We get

\boxed{P(X\le 3)=\dfrac{e-1}e\approx0.632}

c. Same procedure as in (b). We have

P(1\le X\le3)=P(X\le3)-P(X\le1)

and

P(X\le1)=\displaystyle\int_{-\infty}^1f_X(x)\,\mathrm dx=\frac29\int_0^1xe^{-x^2/9}\,\mathrm dx=\frac{e^{1/9}-1}{e^{1/9}}

Then

\boxed{P(1\le X\le3)=\dfrac{e^{8/9}-1}e\approx0.527}

7 0
3 years ago
What is the decimal multiplier to increase by 3%?
nlexa [21]
If you want to increase something by 3%, you would ADD 100% to it, so:
3% + 100% = 103%
Then you divide it by 100 to turn it into a decimal, so:
103% / 100 = 1.03
So to increase by 3%, the multiplier would be 1.03



If you wanted to decrease by 3%, you would SUBTRACT 100% from 3%, so:
100% - 3% = 97%
And then you would divide 97% by 100 to turn it into a decimal (multiplier), so:
97% / 100 = 0.97
So to decrease by 3%, the multiplier would be 0.97
7 0
3 years ago
Drag and drop numbers into the boxes so that the paired values are in a proportional relationship.
mezya [45]

Answer:

A=6 and B=4.5

Step-by-step explanation:

You are given table

\begin{array}{cccccc}x&2&4&[A]&7&9\\y&1&2&3&3.5&[B]\end{array}

If the paired values are in a proportional relationship, then

\dfrac{2}{1}=\dfrac{4}{2}=\dfrac{[A]}{3}=\dfrac{7}{3.5}=\dfrac{9}{[B]}.

Note that

\dfrac{2}{1}=\dfrac{4}{2}=\dfrac{7}{3.5}=2,

then

\dfrac{[A]}{3}=2\Rightarrow [A]=6,\\ \\\dfrac{9}{[B]}=2\Rightarrow [B]=\dfrac{9}{2}=4.5.

4 0
3 years ago
Other questions:
  • What is 506,709 in word form
    10·2 answers
  • At the supermarket you can fill your own honey bear container. A customer buys 12 oz of honey for $5.40.
    15·1 answer
  • Draw the meaning of bar diagram
    8·1 answer
  • Need help quickly please
    8·1 answer
  • Which best completes the following sentence?
    7·2 answers
  • Payton plays 15 games of fortnite in 15 minutes. If he maintains this rate, how many games will he play in 3 hours
    12·2 answers
  • Four less than half a number is 15. Find a number.
    14·2 answers
  • Find the area of the surface generated when the given curve is revolved about the given axis. 5x^1/3
    5·1 answer
  • A medical equipment industry manufactures X-ray machines. The unit cost C (the cost in dollars to make each X-ray machine) depen
    11·1 answer
  • QUESTION ON PIC‼️❓THX
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!