3 years ago

The mass of 0.375 moles of the compound H2XO4 is 54.36 g. Identify X.

Chemistry

1 answer:

pickupchik [31]3 years ago

3 0

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Percentage of mass of solute in aqueous phase is 28.57%.

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$(q)_{aq}$ - Fraction of solute in aqueous phase.

$(q)_{aq}=\frac{V_{aqueous}}{DV_{organic}+V_{aqueous})}$

$V_{aqueous}$ = Used volume of aqueous solution

$V_{organic}$ = Used volume of organic solution

D = partition coefficient.

$(q)_{aq}=\frac{100ml}{(2.5\times100)+100\,ml}=0.2857$

Mass of solute in aqueous phase = $0.2857\times 5g=1.428g$

$Mass\,percentage = \frac{1.428}{5.0}\times 100=28.57$

Therefore, Percentage of mass of solute in aqueous phase is 28.57%.

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