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Lynna [10]
3 years ago
6

Chemistry- "write the products expected from each acid-base reaction shown below........

Chemistry
1 answer:
Dahasolnce [82]3 years ago
8 0
1.) NaOH + HCl  →  NaCl  +  H₂O
<span>
2.) Ca(OH)</span>₂ <span> +  H</span>₂<span>SO4  </span>→<span>  CaSO</span>₄ +  2H₂O
<span>
3.) 2HCl +Ba (OH)2  </span>→ <span> BaCl</span>₂  +  2H₂O
<span>
4.) HNO3 + LiOH   </span>→  <span> LiNO</span>₃ <span> +  H</span>₂O
<span>
5.) H</span>₂CO₃ + NaOH  →  Na₂CO₃  +  H₂O
<span>
6.) KOH  +  HC</span>₂H₃O₂  →  KC₂H₃O₂  <span>+  H</span>₂O
<span>
7.) Ba(OH)2 + HNO2  </span>→<span> Ba(NO</span>₂)₂<span>  +  H</span>₂O
<span>
8.) H</span>₂<span>SO</span>₃<span> + 2NaOH  </span>→<span>  Na</span>₂SO₃  <span>+  2H</span>₂O
<span>
9.) H</span>₃<span>PO</span>₄<span> + 3KOH  </span>→<span>   K</span>₃PO₄  <span>+   3H</span>₂O 
<span>
10.) 2HBr + Ca(OH)2  </span>→<span>  CaBr</span>₂  +  2H₂O


The reason why water is so recurrent is because of the general form that says:   ACID  +  BASE  →  SALT  +  WATER

I took the liberty of balancing the equations.
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How many grams of water will be produced from 50 g hydrogen reacting with 50 g oxygen?
DanielleElmas [232]

We need to first come up with a balanced equation:


4H+O_{2} → 2H_{2}O


We know that the molar ratio of hydrogen to oxygen to water now is 4:1:2.


Converting the amount of grams given to moles is as follows:


Hydrogen: \frac{1mole}{1.008g}*50g=49.6mol


Oxygen: \frac{1mole}{15.999g}*50g=3.125mol


We know now that the limiting reactant is oxygen. We can then know that the number of moles of water are produced are double the number of moles of oxygen used due to the ratio that we established at the beginning - 4:1:2.


So we now can use 6.25 moles of water as the amount produced.


Then we convert moles of water to grams:


\frac{18.015g}{1mole} *6.25mol=112.59g


Now we know that there are 112.59g of water produced when we start with 50g of hydrogen and 50g of water.

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3 years ago
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A certain radioactive element has a half-life of one hour. If you start with 40.0 grams of the element at noon, how much of the
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Need help with this question.... Next to each Formula, write the number of atoms of each element found in one unit of the compou
Andrew [12]

Answer:

The number of atoms present in one unit of the following compounds is:

a). Potassium Iodide , KI = 2

b).Sodium Sulfide, Na_{2}S = 3

c). Silicon Dioxide , SiO_{2} = 3

d). Carbonic Acid ,H_{2}CO_{3} = 6

Explanation:

Atomicity : It is defined as the number of atoms that are present in a given molecule/compound.

Atom : The smallest unit of matter is called atom. For e.g O is atom of oxygen but O_{2} is not an atom , it is molecule of oxygen .

O_{2} molecule has 2 atoms of Oxygen

Similarly  Na , K , Fe are atoms but O_{2} ,CO_{2} ,N_{2},H_{2}  are molecules

a).Potassium Iodide

KI = 1 atom of K + 1 atom of I

Total atoms = 2

b) Sodium Sulfide

Na_{2}S = 2 atoms of Na + 1 atom of S

Total atoms = 3

c) Silicon Dioxide

SiO_{2} = 1 atom of Si + 2 atoms of O

Total atoms = 3

d) Carbonic Acid

H_{2}CO_{3} = 2 atom of H + 1 atom of C + 3 atom of O

= 2+1+3

Total atoms = 6

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