Answer:
13.2 g Na2CO3
Explanation:
Convert 10.0 g NaOH to mol.
10.0 g x 1 mol/39.997 g = 0.250 mol
Use mol ration given by the equation: 2 mol NaOH to 1 mol Na2CO3
0.250 mol NaOH x 1 mol Na2CO3/2 mol NaOH = 0.125 mol Na2CO3
Finally, convert the moles of Na2CO3 to grams.
0.125 mol Na2CO3 x 105.99 g/1 mol = 13.2 g
Answer:
1.48 × 10²⁴ atoms
Explanation:
Step 1: Calculate the moles of argon
Argon is a noble gas, whose molar mass is 39.95 g/mol. We will use this data to find the moles corresponding to 98.1 grams of argon.
Step 2: Calculate the atoms of argon
In order to calculate the number of atoms of argon in 2.46 moles of argon, we have to consider the Avogadro's number: there are 6.02 × 10²³ atoms of Ar in 1 mole of Ar.
When a substance goes from being a liquid to a gas it evaporates, or boils away. Think of boiled eggs.
Answer:
Explanation:
As an example, the following cell reaction: Zn(s) + Cu2+(aq) → Zn2+(aq) + Cu(m) generates a cell voltage of +1.10 V under standard conditions. Calculate and enter delta G degree (with 3 sig figs) for this reaction in kJ/mol.
Zn(s) + Cu2+(aq) → Zn2+(aq) + Cu(m)
ΔG = ΔG° + RTInQ
Q = 1
ΔG = ΔG°
ΔG = =nFE°
n=no of electrons transfered.
E° = 1.1v
ΔG° = -2 * 96500 * 1.10
= -212300J
ΔG° =-212.3kJ/mol
<h3>Therefore, the ΔG° = -212.3kJ/mol</h3>
Answer
The negative ion is larger than the original atom.
Explanation:
This means that with fewer electrons but the same number of positive protons, the size of the ionic radius will decrease.
I hope this helped!
