The triangles shown below must be congruent. True or false

Mathematics

2 answers:

ipn [44]2 years ago

8 0

True is the answer .....

Katen [24]2 years ago

6 0

Answer:

true

Step-by-step explanation:

they're not dilated in anyway.

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A revenue department is under orders to reduce the time small business owners spend filling out pension form ABC-5500. Previousl

Goshia [24]

Considering the situation described, we have that:

The appropriate null hypotheses is $H_0: \mu = 5.2$ .

The appropriate alternative hypotheses is $H_1: \mu < 5.2$ .

<h3>What are the hypotheses tested?</h3>

At the null hypotheses, it is tested if the mean has not been reduced, that is, it still is of 5.2 hours, hence:

$H_0: \mu = 5.2$ .

At the alternative hypothesis, it is tested if the mean has been reduced, that is, it is now of less than 5.2 hours, hence:

$H_1: \mu < 5.2$

More can be learned about hypotheses tests at brainly.com/question/26454209

4 0

1 year ago

The family of solutions to the differential equation y ′ = −4xy3 is y = 1 √ C + 4x2 . Find the solution that satisfies the initi

slega [8]

Answer:

The correct option is 4

Step-by-step explanation:

The solution is given as

$y(x)=\frac{1}{\sqrt{C+4x^2}}$

Now for the initial condition the value of C is calculated as

$y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(-2)=\frac{1}{\sqrt{C+4(-2)^2}}\\4=\frac{1}{\sqrt{C+4(4)}}\\4=\frac{1}{\sqrt{C+16}}\\16=\frac{1}{C+16}\\C+16=\frac{1}{16}\\C=\frac{1}{16}-16$

So the solution is given as

$y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}$

Simplifying the equation as

$y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1-256+64x^2}{16}}}\\y(x)=\frac{\sqrt{16}}{\sqrt{{1-256+64x^2}}}\\y(x)=\frac{4}{\sqrt{{1+64(x^2-4)}}}$