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3 years ago

Carlos went kayaking and burned 380 calories. It's a hot day, and he decides to

Mathematics

2 answers:

svetlana [45]3 years ago

4 0

The answer is the chicken wrap

maks197457 [2]3 years ago

3 0

The chicken wrap as it replaces all the lost calories!

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B. Using your answer in letter a or write the equation of the line in the form Ax + By = C

Svetradugi [14.3K]

Answer:

Step-by-step explanation:

(1, 5.5) ; (2, 9)

Slope = $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\$

$= \frac{9-5.5}{2-1}\\\\=\frac{3.5}{1}\\\\= 3.5$

= 7/2

m = 7/2 ; (2 , 9)

y - y1 =m(x -x1)

$y - 9 = \frac{7}{2}(x- 2)\\\\y - 9 = \frac{7}{2}x - \frac{7}{2}*2\\\\y -9 = \frac{7}{2}x - 7\\\\y = \frac{7}{2}x - 7 + 9\\\\y = \frac{7}{2}x + 2$

Multiply the equation by 2

$2y = 2*\frac{7}{2}x + 2 *2\\\\2y = 7x + 4\\\\7x - 2y = -4\\$

4 0

3 years ago

1. The price of a TV is $295. The price of a

TiliK225 [7]

Answer:

The price of the projector is $1,180.

Step-by-step explanation:

295 × 4 = 1,180

5 0

3 years ago

I WILL GIVE YOU BRAINLIEST!!

ollegr [7]

Answer:

32 goldfish

Step-by-step explanation:

Given:

Number of fish tanks = 8
Volume of water per fish tank = 5,544 in³
Water required by 1 goldfish = min 1,386 in³

Number of fish per tank = water per tank ÷ water per goldfish

= 5544 ÷ 1386

= 4

Therefore, each tank can hold a maximum of 4 goldfish.

Greatest number of goldfish = number of tanks × fish per tank

= 8 × 4

= 32

3 0

2 years ago

24 question thank you

Alona [7]

You would just do 3/5 * 55 = 33 movies were new releases.

8 0

3 years ago

Read 2 more answers

The total number of people at a football game was 5600. Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.

rewona [7]

Answer:

1100 field-side tickets and 4500 end-zone tickets.

Step-by-step explanation:

Let x represent number of field side tickets and y represent number of end-zone tickets.

We have been given that the total number of people at a football game was 5600. We can represent this information in an equation as:

$x+y=5600...(1)$

$y=5600-x...(1)$

We are also told that Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.

Cost of x field side tickets would be $40x$ and cost of y end-zone tickets would be $20y$ .

The total amount of money received for the tickets was $134000. We can represent this information in an equation as:

$40x+20y=134000...(2)$

Upon substituting equation (1) in equation (2), we will get:

$40x+20(5600-x)=134000$

$40x+112000-20x=134000$

$20x+112000=134000$

$20x+112000-112000=134000-112000$

$20x=22000$

$\frac{20x}{20}=\frac{22000}{20}$

$x=1100$

Therefore, 1100 field side tickets were sold.

Upon substituting $x=1100$ in equation (1), we will get:

$y=5600-1100$

$y=4500$

Therefore, 4500 end-zone tickets were sold.

3 0

3 years ago