When preparing an emergency supply kit for a family, which is the minimun number of days the supplies shoulds last

Please help! Will give brainly, 50 points!! I don't understand! I just need this to give me a boost on my other questions.

harina [27]

Answer:

The answer to your question is: c = 353 mi/h; Ф = 7.3°

Explanation:

You can see the picture below

To solve this problem, just imagine a right rectangle which the legs is 350 mi/h and 45 mi/h and we are going to find the hypotenuse.

c² = a² + b²

c² = 350² + 45²

c² = 122500 + 2025

c² = 124525

c = 352.9 ≈ 353 mi/h

tanФ = 45/ 350

tan Ф = 0.12

Ф = 7.3°

8 0

4 years ago

When you drop a 0.43 kg apple, Earth exerts

N76 [4]

The magnitude of the Earth's acceleration is $7.0\cdot 10^{-25} m/s^2$

Explanation:

First of all, we start by calculating the magnitude of the force exerted by the apple on the Earth. According to Newton's third law, this is equal to the force exerted by the Earth on the apple, which is the weight of the apple, given by:

$F=mg$

where

m = 0.43 kg is the mass of the apple

$g=9.8 m/s^2$ is the acceleration of gravity

Substituting,

$F=(0.43)(9.8)=4.2 N$

Now we can find the Earth's acceleration by applying Newton's second law:

$F=Ma$

where:

F = 4.2 N is the net force exerted by the apple on the Earth

$M=5.98\cdot 10^{24} kg$ is the mass of the Earth

a is the Earth's acceleration

And solving for a, we find:

$a=\frac{F}{M}=\frac{4.2}{5.98\cdot 10^{24}}=7.0\cdot 10^{-25} m/s^2$

Learn more about Newton laws of motion:

brainly.com/question/3820012

brainly.com/question/11411375

#LearnwithBrainly

8 0

4 years ago

Which term describes the difference in electrical charge across a membrane? View Available Hint(s) Which term describes the diff

Zinaida [17]

Answer:

Membrane potential

Explanation:

Membrane potential is describes the difference in electrical charge across a membrane.

The difference in potential between exterior and interior of the biological cell is known as Membrane potential.Generally it is denoted by millivolts like mV and varies from -80 V to -40 V.

So the answer is Membrane potential

4 0

4 years ago

13. A lever does 5.0 J of work on a 0.10-kg ball bearing in a pinball machine. The ball's

shusha [124]

Answer:

The resulting speed of the ball is;

10 m/s

Explanation:

The given parameters are;

The amount of work done by the lever = 5.0 J

The mass of the ball on which the work is done, m = 0.10 kg

By the principle of conservation of energy, we have;

The work done by the lever = The kinetic energy. K.E., gained by the ball

The kinetic energy, K.E., is given by K.E. = 1/2·m·v²

Where, for the ball, we have;

m = The mass of the ball

v = The resulting speed of the ball

Therefore, by substituting the known values, we have;

The work done by the lever = 5.0 J = The kinetic energy. K.E., gained by the ball = 1/2 × m × v² = 1/2 × 0.10 kg × v²

∴ 5.0 J = 1/2 × 0.10 kg × v²

v² = 5.0 J/(1/2 × 0.10 kg) = 100 m²/s²

v = √(100 m²/s²) = 10 m/s

The resulting speed of the ball, v = 10 m/s.

6 0

3 years ago

What is the gravitational force between two masses of 15kg each, when their centers are 0.25m? Could you detect this force with

Lunna [17]

Well I don't know !
Let's work it out.

The gravitational force between two objects is

   F = G · M₁·M₂ / R²     .

'G' is the 'universal gravitational constant'. We could look it up.
'M₁' is the mass of one object
'M₂' is the mass of the other object
'R' is the distance between their centers.

It looks complicated, but stay with me. We can do this !
We know all the numbers, so we can calculate the force.

'G' is 6.67 x 10⁻¹¹ newton·meter² / kg² (I looked it up. You're welcome.)
'M₁' is 15 kg
'M₂' is 15 kg
'R' is 0.25 meter.

Now it's time to pluggum in.

   F = G · M₁·M₂ / R²

   = (6.67 x 10⁻¹¹ newton·meter² / kg²) · (15 kg) · (15 kg) / (0.25 m²)

   = (6.67 x 10⁻¹¹ · 15 · 15 / 0.0625) N·m²·kg·kg / kg²·m²

   =    2.4 x 10⁻⁷ Newton .

That a force equivalent to about 0.00000086 of an ounce.
This is the answer to part-a.

Concerning the answer to part-b ...
Personally, I could not detect this force, no matter what kind of equipment
I had. But I am just a poor schlepper engineer, educated in the last Century,
living out my days on Brainly and getting my kicks from YouTube videos.
I am not pushing the box to the envelope, or thinking outside the cutting
edge ... whatever.
I am sure there are people ... I can't name them, because they keep a
low profile, they stay under the radar, they don't attract a lot of media
attention, their work is not as newsworthy as the Kardashians, and plus,
they seldom call me or write to me ... but I know in my bones that there
are people who have measured the speed of light to NINE significant figures,
aimed a spacecraft accurately enough to take close-up pix of Pluto ten years
later, and detected gravity waves from massive blobs that merged 13 billion
years ago, and I tell you that YES ! THESE guys could detect and measure
a force of 0.86 micro-ounce if they felt like it !

4 0

3 years ago