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Fynjy0 [20]
3 years ago
10

Two circles are drawn in a 12-inch by 14-inch rectangle. Each circle has a diameter of 6 inches. If the circles do not extend be

yond the rectangular region, what is the greatest possible distance (in inches) between the centers of the two circles?
Physics
1 answer:
Dennis_Churaev [7]3 years ago
6 0

Answer:

d = 10 inch

Explanation:

The farthest distance between the centers, is along the diagonal of the rectangle. Therefore, we need to calculate the diagonal of the rectangle, but counting the fact that we have both circles.

So if, one side is 12 inch, and the other is 14 inch, we can use the Pitagoras theorem which is:

d = √(a²) + (b)²

Where a and b, are the lenght of the rectangle, but without the lenght  of the diameter of both circles.

With this, the expression is this:

d = √(14 - 6)² + (12 - 6)²

d = √64+36

d = √100

d = 10 inches

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A charge of q= +15 uC moves in a Northeast direction with a speed 5 m/s, 25 degrees East of a magnetic field, pointing North, wi
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Explanation:

It is given that,

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Velocity, v=(5\ cos25)i+(5\ sin25)j

v=[(4.53)i+(2.11)j]\ m/s

We need to find the magnitude of force on the charge. Magnetic force is given by :

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F=15\times 10^{-6}[(4.53i)\times (0.08)\ j]

F=0.00000543\ kN

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6 0
3 years ago
5) The motion that repeats itself in equal intervals of time is called<br>olaration is equal to​
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Answer:

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Compounds formed from the attraction of oppositely charged ions are called
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Answer:

The answer is below

Explanation:

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