Answer:
756.88 Volts will be the potential difference across each capacitor.
Explanation:
Q = Charge on capacitor
C = Capacitance
V = Voltage across capacitor
Capacitance of first capacitor = 
Charge of first capacitor = 
Voltage across first capacitor = 
Capacitance of first capacitor = 
Charge of second capacitor = 
Voltage across first capacitor = 
Both the capacitors are disconnected and positive plates are now connected to each other and the negative plates are connected to each other. These capacitors are connected in parallel combination.
Total charge = Q
Total capacitance in parallel combination:
Potential across both capacitors = V
756.88 Volts will be the potential difference across each capacitor.
The answer is the Milky Way .
Answer:
The average induced emf is 29.06 V
Explanation:
Given;
radius of the circular loop, r = 12.0 cm = 0.12 m
magnetic field strength, B = 1.8 T
time interval = 2.8 ms = 0.0028 s
Area of the circular loop, A = πr² = π (0.12)² = 0.0452 m²
where;
B is magnetic field
A is area
t is time
substitute the values given in the above equation to calculate the average emf that will be induced in the wire loop during the extraction process.
Therefore, the average induced emf is 29.06 V
Answer: the ball will have a charge of 8x10^8C when we remove 5x10^27 electrons.
Explanation:
If the sphere is neutral, then the charge of the sphere is 0C
Now, when we remove an electron (-1.6*10^-19 C) we are subtracting a negative number, so the new charge of the sphere is: 1.6*10^-19 C
Now, for N removed electrons, the charge of the sphere is:
N*1.6*10^-19 C
We want to find the number N when:
N*1.6*10^-19 C = 8.0x 10^8 C
N = (8.0/1.6)x10^(8 + 19) = 5x10^27 electrons.
