The balanced equation for the formation of ammonia is as follows
N₂ + 3H₂ ---> 2NH₃
stoichiometry of N₂ to H₂ is 1:3
we need to find the moles of N₂, volume of N₂ has been given
molar volume is where 1 mol of any gas occupies a volume of 22.4 L at STP.
if 22.4 L is occupied by 1 mol
then 3.5 L of gas is occupied by - 3.5 L / 22.4 L/mol = 0.16 mol
number of moles of N₂ present - 0.16 mol
1 mol of N₂ requires 3 mol of H₂
therefore 0.16 mol of N₂ requires - 3 x 0.16 = 0.48 mol of H₂
mass of H₂ required - 0.48 mol x 2 g/mol = 0.96 g
0.96 g of H₂ is required
Answer:
Chlorine
Explanation:
Chlorine has an atomic number of 17 and a configuration of 2, 8, 7. In the outermost shell, it has 7 seven electrons which means that it needs just one more electron to attain an octet configuration in that shell. Therefore it's can react quickly with any nearby nucleophile.
Answer:
it must be testable I think that's the answer
C5H12(g) + 8 O2(g) = 5 CO2(g) + 6H2O(g)
molar ratio of H2O to O = 6:8
<span>we have 0.200 moles of H2O so we need 0.200 * 8/6 moles of O2 = 0.267 moles of O2
Therefore, there will be 0.267 moles of O2 gas required to yield 0.2 moles of H20.
I hope my answer has come to your help. Thank you for posting your question here in Brainly.
</span>
