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3 years ago

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Question 12 of 32

1 answer:

Sidana [21]3 years ago

8 0

Answer:

A. Antoine-Laurent Lavoisier

Explanation:

Hope this helped!

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Labels of many food products have expiration dates, at which point they are typically removed from the supermarket shelves. A pa

White raven [17]

Answer:

Explanation:

Since it first order, we use order rate equation

In ( $\frac{A1}{A0}$ ) = -kt where A1 is the final quality = 0.8 (80%), A0 is the initial quality = 1 ( 100%)

also, t half life = $\frac{In2}{k}$ where k is rate constant

k = $\frac{In 2}{45 days}$ = 0.0154

In ( $\frac{0.8}{1}$ ) = - 0.0154 t

-0.223 / -0.0154 = t

t = 14.49 approx 14.5 days from the date the yogurt was packaged

6 0

3 years ago

What happens to the particles during solid to a liquid

Ratling [72]

the particles from solid to liquid start to move around faster then it was at the first state

3 0

3 years ago

Solutions can only be separated by using distillation not filtration. Why can't a solution be filtered? Explain using the terms

garri49 [273]

<h2>Solutions</h2>

Explanation:

Solutions are formed when a solute gets dissolved in a solvent. The solid that gets dissolved is called solute whereas the liquid in which the solid gets dissolved is called the solvent. On dissolving, the particles of the solute gets incorporated between the inter-particle space of the solvent. This means that there is no significant difference between the particle size of solute and solvent. However the boiling points of solutions can differ significantly. This is the reason, the solutions cannot be separated by the method of filtration but by the method of distillation.

5 0

3 years ago

The combustion of 1.5011.501 g of fructose, C6H12O6(s)C6H12O6(s) , in a bomb calorimeter with a heat capacity of 5.205.20 kJ/°C

avanturin [10]

Answer : The internal energy change is -2805.8 kJ/mol

Explanation :

First we have to calculate the heat gained by the calorimeter.

$q=c\times (T_{final}-T_{initial})$

where,

q = heat gained = ?

c = specific heat = $5.20kJ/^oC$

$T_{final}$ = final temperature = $27.43^oC$

$T_{initial}$ = initial temperature = $22.93^oC$

Now put all the given values in the above formula, we get:

$q=5.20kJ/^oC\times (27.43-22.93)^oC$

$q=23.4kJ$

Now we have to calculate the enthalpy change during the reaction.

$\Delta H=-\frac{q}{n}$

where,

$\Delta H$ = enthalpy change = ?

q = heat gained = 23.4 kJ

n = number of moles fructose = $\frac{\text{Mass of fructose}}{\text{Molar mass of fructose}}=\frac{1.501g}{180g/mol}=0.00834mole$

$\Delta H=-\frac{23.4kJ}{0.00834mole}=-2805.8kJ/mole$

Therefore, the enthalpy change during the reaction is -2805.8 kJ/mole

Now we have to calculate the internal energy change for the combustion of 1.501 g of fructose.

Formula used :

$\Delta H=\Delta U+\Delta n_gRT$

or,

$\Delta U=\Delta H-\Delta n_gRT$

where,

$\Delta H$ = change in enthalpy = $-2805.8kJ/mol$

$\Delta U$ = change in internal energy = ?

$\Delta n_g$ = change in moles = 0 (from the reaction)

R = gas constant = 8.314 J/mol.K

T = temperature = $27.43^oC=273+27.43=300.43K$

Now put all the given values in the above formula, we get:

$\Delta U=\Delta H-\Delta n_gRT$

$\Delta U=(-2805.8kJ/mol)-[0mol\times 8.314J/mol.K\times 300.43K$

$\Delta U=-2805.8kJ/mol-0$

$\Delta U=-2805.8kJ/mol$

Therefore, the internal energy change is -2805.8 kJ/mol

5 0

3 years ago

How many bonding pairs in br2o

Evgen [1.6K]

There are 22 bonding parts

5 0

3 years ago