<u>Answer:</u> The amount of water required to prepare given amount of salt is 398.4 mL
<u>Explanation:</u>
To calculate the volume of solution, we use the equation used to calculate the molarity of solution:
We are given:
Molarity of solution = 0.16 M
Given mass of manganese (II) nitrate tetrahydrate = 16 g
Molar mass of manganese (II) nitrate tetrahydrate = 251 g/mol
Putting values in above equation, we get:
Volume of water = Volume of solution = 398.4 mL
Hence, the amount of water required to prepare given amount of salt is 398.4 mL
I had the same question last week and my answer was C. Try that.
Answer:
1.88 M
Explanation:
The following data were obtained from the question:
Mole of NaCl = 0.47 mole
Volume of solution = 0.25L
Molarity =?
Molarity is defined as the mole of solute per unit litre of the solution. It can represented mathematically as:
Molarity = mole /Volume
Using the above formula, the molarity of the salt water solution can be obtained as follow:
Molarity = 0.47/0.25
Molarity = 1.88 M
Option “A” is the crest of the wave because it’s the maximum value of upward displacement within a cycle.
It's called Ice Wedging :)
