Answer:
1. Josh's father: f Josh: f/2 - 2
2. f + (f/2 - 2) ≥ 49
3. 3/2 f - 2 ≥ 49
3/2 f ≥ 51
3f ≥ 102
f ≥ 34
4. 34
2/15 sorry if it’s wrong all I did was just divide both of them
Answer:
3. Option No. 2:
6x + 2y = 22
3x + 3y = 18
4. Option No. 2:
$2.50
Step by step explanation:
4. 6x + 2y = 22
(3x + 3y = 18) * 2
- Negate
6x + 2y = 22
6x + 6y = 36
2y - 6y = 22 - 36
-4y = -14
y = -14/-4
y = 3.5
An order of onion rings = $3.50
- Substitute to find for x
6x + 2(3.5) = 22
6x + 7 = 22
6x = 22 - 7
6x = 15
x = 15/6
x = 2.5
An order of French fries = $2.50
Answer:
decrease of 64.3%
Step-by-step explanation:
Percentage change can be calculated from ...
pct change = ((new value)/(original value) -1) × 100%
= (50/140 -1) × 100%
= (-9/14)×100% = -64 2/7% ≈ -64.3%
The price of crude fell about 64.3% in that period.
Standard equation of a circle: <em>(x-h)² + (y-k)² = r²</em> where <em>(h, k)</em> is the center and <em>r </em>is the radius. In the case of our equation here, <em>(x-5)² + (y+3)² = 25</em>, we can conclude that our circle has a center at (5, -3) and a radius of 5 units.
We can use the distance formula with the center (5, -3) and our point (2, 3) to see how far away they are...if the distance between them is less than the radius of the circle, it is on the interior. If it's equal, it's on the circle. If it's greater, it's on the exterior.
Distance =
![\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%28y_2-y_1%29%5E2%2B%28x_2-x_1%29%5E2%7D)
Distance =
![\sqrt{(-3-3)^2+(5-2)^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%28-3-3%29%5E2%2B%285-2%29%5E2%7D)
Distance =
![\sqrt{(-6)^2+3^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%28-6%29%5E2%2B3%5E2%7D)
Distance =
![\sqrt{36+9}](https://tex.z-dn.net/?f=%5Csqrt%7B36%2B9%7D)
Distance =
![\sqrt{45}\approx6.7082](https://tex.z-dn.net/?f=%5Csqrt%7B45%7D%5Capprox6.7082)