Answer:
C' (-4 , 2)
slope of new line = line "L" = -2
Step-by-step explanation:
C (x₀,y₀): (0,2) dilation center (h,k): (2,2) scale factor (sf): 3
C' (x,y)
x = 2 + 3*(0-2) = -4 x = h + sf*(x₀ - h)
y = 2 + 3*(2-2) = 2 y = k + sf*(y₀ - k)
C' (-4 , 2)
slope of new line = line "L" = -2
Two complementary angles add up to 90 degrees. Hence, the problem can be set up and solved. Let x represents one angle and 5x represent the angle that is 5 times greater:x + 5x = 90 (simplify)6x = 90 (next divide both sides by 6 to find the value of x [the smaller angle])x = 15 (this is the smaller angle, next subtract 15 from 90 to find the greater angle)90 - 15 = 75 (this is the greater angle which is 5 times that of its complement) <span>90 take away 73...</span>
The weight of Euclid is 10.625 pounds, and the weight of Riemann is 21.25 pounds.
- <em>Let the current weight of Euclid = x</em>
- <em>Let the current weight of Pythagoras = T</em>
- <em>Let the January weight of Pythagoras = y</em>
The expression that represents the given scenario is written as;
- when Pythagoras lost 13 pounds: T = y - 13
- when Pythagoras gains 1.2 times Euclid's weight: = T + 1.2x
when Pythagoras weight is 1/4 pound less than weight in January:
T + 1.2x + 0.25 = y
y- 13 + 1.2x + 0.25 = y
1.2x - 12.75 = 0
Euclid's weight is calculated as follows;
1.2x = 12.75
![x = \frac{12.75}{1.2} \\\\x = 10.625 \ pounds](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B12.75%7D%7B1.2%7D%20%5C%5C%5C%5Cx%20%3D%2010.625%20%5C%20pounds)
The weight of Riemann is calculated as follows;
![= 2 (10.625)\\\\= 21.25 \ pounds](https://tex.z-dn.net/?f=%3D%202%20%2810.625%29%5C%5C%5C%5C%3D%2021.25%20%5C%20pounds)
Learn more about word problem to algebra here: brainly.com/question/21405634