What activity is mainly a strength training excerise?

a race car driver must average 203 km/h over the course of a time trial lasting ten laps. If the first nine laps were done at 19

sashaice [31]

Answer:

speed for last lap is 247.89 km/h

Explanation:

given data

velocity v1 = 203 km/h

velocity v2 = 199 km/h

no of lap n = 10

to find out

average speed for last lap

solution

we consider here distance d for 1 lap

so in first 9 lap time taken is

t1 = distance / velocity v2

t1 = 9d / 199 ...............1

and

for 10 lap time is

t2 = 10d / 203 .............2

so from 1 and 2 equation time for last lap

last lap time t3 = t2 - t1

t3 = 10d / 203 - 9d / 199

t3 = 0.004034 d

so speed for last lap is

speed = distance / time

speed = d / 0.004034 d

speed = 247.89 km/h

so speed for last lap is 247.89 km/h

4 0

3 years ago

Which of the following will attract one another? A. The north pole of magnet and the south pole of another magnet B. The north p

Elena L [17]

A. is the correct answer

7 0

3 years ago

A wooden rod of negligible mass and length 84.0 cm is pivoted about a horizontal axis through its center. A white rat with mass

Mandarinka [93]

Answer:

v = 2.029 m/s

Explanation:

Given

L = 84.0 cm ⇒ R = 0.5*L = 0.5*84 cm = 42 cm = 0.42 m

m₁ = 0.600 kg

m₂ = 0.200 kg

g = 9.8 m/s²

u₁ = u₂ = 0 m/s

v₁ = ?

v₂ = ?

Due to gravity, the bar oscillates and becomes vertical. The mass that occupies the lower position is the one with the highest torque. The one that reduces the potential energy (the system tends to the position of minimum energy). This is achieved if the mass that goes down is 0.6kg (that goes down 42cm) and the one that goes up is 0.2kg (goes up 42cm).

In this system mechanical energy is conserved, so we can match its value in the horizontal position with the one in the vertical.

then

Ei = Ki + Ui = 0.5*(m₁+m₂)*(0)² + (m₁+m₂)*9.8*(0) = 0 J

Ef = Kf + Uf

⇒ Kf = 0.5*(m₁+m₂)*v² = 0.5*(0.6+0.2)*v² = 0.4*v²

⇒ Uf = m₁*g*h₁ + m₂*g*h₂ = 0.6*9.8*(-0.42) + 0.2*9.8*0.42 = - 1.6464

⇒ Ef = Kf + Uf = 0.4*v² - 1.6464

Since

0 = 0.4*v² - 1.6464 ⇒ v = 2.029 m/s

v is the same value due to the wooden rod is pivoted about a horizontal axis through its center and the masses are on opposite ends.

v₁ = v₂ = v ⇒ ω₁*R₁ = ω₂*R₂ ⇒ ω₁*R = ω₂*R ⇒ ω₁ = ω₂ = ω

⇒ v = ω*R

5 0

3 years ago

What statement provides an example of designing a solution in the technological design process? Aerospace engineers need a light

scoundrel [369]

Answer:

i have no idea some one help

Explanation:

6 0

3 years ago

Read 2 more answers

If two children, with masses of 16 kg and 24 kg , sit in seats opposite one another, what is the moment of inertia about the rot

Elena-2011 [213]

Answer:

The moment of inertia about the rotation axis is 117.45 kg-m²

Explanation:

Given that,

Mass of one child = 16 kg

Mass of second child = 24 kg

Suppose a playground toy has two seats, each 6.1 kg, attached to very light rods of length r = 1.5 m.

We need to calculate the moment of inertia

Using formula of moment of inertia

$I=I_{1}+I_{2}$

$I=(m+m_{1})\times r^2+(m+m_{2})\times r^2$

m = mass of seat

m₁ =mass of one child

m₂ = mass of second child

r = radius of rod

Put the value into the formula

$I=(16+6.1)\times(1.5)^2+(24+6.1)\times(1.5)^2$

$I=117.45\ kg-m^2$

Hence, The moment of inertia about the rotation axis is 117.45 kg-m²

8 0

3 years ago