Answer:
B) Its horizontal velocity component is the same as it was just as it was launched
Explanation:
From dynamic we know that free falling objects had two components of velocity
The only acceleration that takes place in this case is gravity in the y-component of velocity
Since a=0 and that means that the velocity at the y-component changes with time but the horizontal component remain the same
This means that the horizontal velocity is not 0 but is <u><em>the same as it was just as it was launched</em></u>
Answer:
south of east
Explanation:
= 3 m/s
= north of east
= 6 m/s
= south of east = north of east
x and y component of
x and y component of
Magnitude
Direction
The magnitude of the change in velocity vector is and the direction is south of east.
Answer: In the planet there is life and the star is a store of energy where the planet gets its light, life and energy.
Explanation:
Answer:
Here not any option is matching but only (A) option is near to our answer.
The frictional force is 126.046 N
Explanation:
Given:
Mass of bullet kg
Thickness of sand bag m
Initial bullet velocity
Final bullet velocity
According to the work energy theorem,
Work done by friction force is equal to change in kinetic energy.
Here we have to find friction force
N
Here not any option is matching but only (A) option is near to our answer.
Therefore, the frictional force is 126.046 N
Answer:
Wavelength of AM radio wave = 0.125 meter
Explanation:
Given:
Frequency of AM radio wave = 24 Hz
Velocity of AM radio wave = 3 m/s
Find:
Wavelength of AM radio wave
Computation:
Wavelength = Velocity / Frequency
Wavelength of AM radio wave = Velocity of AM radio wave / Frequency of AM radio wave
Wavelength of AM radio wave = 3 / 24
Wavelength of AM radio wave = 0.125 meter