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kondaur [170]
3 years ago
5

A

Physics
2 answers:
madam [21]3 years ago
4 0

Answer:

Calculate the acceleration if it took 2 seconds to slow your car down.Explanation:

skelet666 [1.2K]3 years ago
4 0

I need points dog. I am sorry about the inconvenience michael.

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When a force is exerted on an object, work is done only if the object
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Is moving, i'm almost positive

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Changes in behavior of managers, coworkers, and subordinates can be a warning sign before a layoff. True or false
Yakvenalex [24]

Answer:

The correct answer is - true.

Explanation:

Changes in the higher authorities or managers or coworkers can be a warning sign before a layoff, however, a company or organization needs to give an official notice before a particular time period before the layoff.

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3 years ago
An electron is accelerated by a 5.9 kV potential difference. das (sd38882) – Homework #9 – yu – (44120) 3 The charge on an elect
klio [65]

Complete Question

An electron is accelerated by a 5.9 kV potential difference. das (sd38882) – Homework #9 – yu – (44120) 3 The charge on an electron is 1.60218 × 10−19 C and its mass is 9.10939 × 10−31 kg. How strong a magnetic field must be experienced by the electron if its path is a circle of radius 5.4 cm?

Answer:

The magnetic field strength is  B= 0.0048 T

Explanation:

The work done by the potential difference on the electron is related to the kinetic energy of the electron by this mathematical expression

                             \Delta V q = \frac{1}{2}mv^2

      Making v the subject

                             v = \sqrt{[\frac{2 \Delta V * q }{m}] }

 Where m is the mass of electron

              v is the velocity of electron

              q charge on electron

               \Delta V is the potential difference  

Substituting values

         v = \sqrt{\frac{2 * 5.9 *10^3 * 1.60218*10^{-19} }{9.10939 *10^{-31]} }f

            = 4.5556 *10^ {7} m/s

For the electron to move in a circular path the magnetic force[F = B q v] must be equal to the centripetal force[\frac{mv^2}{r}] and this is mathematically represented as

                  Bqv = \frac{mv^2}{r}

making B the subject

                B = \frac{mv}{rq}

r is the radius with a value = 5.4cm = = \frac{5.4}{100} = 5.4*10^{-2} m

Substituting values

                B = \frac{9.1039 *10^{-31} * 4.556 *10^7}{5.4*10^-2 * 1.60218*10^{-19}}

                     = 0.0048 T

                 

7 0
4 years ago
What happens to light that strikes a piece of glass
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