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3 years ago

During a baseball game, a batter hits a high

Physics

2 answers:

SashulF [63]3 years ago

8 0

Answer:

The maximum height of the ball is 36.65 m.

Explanation:

Given that,

Time = 5.47 sec

The ball must be at top point in half of total time.

We need to calculate the height

Using equation of motion

$s = ut+\dfrac{1}{2}gt^2$

Where, s = height

u = initial velocity

g = acceleration due to gravity

Put the value in the equation

$s=0+\dfrac{1}{2}\times9.8\times(\dfrac{5.47}{2})^2$

$s=36.65\ m$

Hence, The maximum height of the ball is 36.65 m.

erastovalidia [21]3 years ago

7 0

Answer:

53.60600 m

Explanation:

5.47 x 9.8

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TiliK225 [7]

Answer:

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Explanation:

The formula for density is mass/volume. If you were to divide 62.44 by 7, you would get 8.92. Since copper is the only metal in this table that has a density of 8.92, that is the answer.

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3 years ago

Two charges, -20 C and +4.7 C, are fixed in place and separated by 3.0 m. a. At what spot along a line through the charges is th

Pani-rosa [81]

The zero net electric field point is at a point that is 0.98 m away from 4.7C charge.If a 14C charge is placed at this point then, force acted on the charge placed at this point is equal to zero.

Explanation:

Let at A both net electric field is zero then

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3 years ago

A wire is stretched right to its breaking point by a 5000 N force. A longer wire made of the same material has the same diameter

leva [86]

Answer:

Equal to 5000N

Explanation:

The stress on the material is defined by force per unit of cross-sectional area. So it depends on the force and the diameter of the wire, which is the same for both wires. The material that defines the breaking point, is also the same. Therefore, both wires have their breaking point the same at 5000N. The wire length plays no role in here.

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3 years ago

A ball is thrown straight up. What will

Papessa [141]

Answer:

velocity at the top: 0 m/s

acceleration at the top: -9.8 m/s²

Explanation:

Assuming up is positive and down is negative;

The velocity of the ball at the top of its path will be 0 m/s and the acceleration will be negative.

The velocity is 0 m/s because the ball does not move at the top of its path, and it switches from a positive velocity to a negative velocity. It must go through 0 in order to go from positive to negative.

The acceleration, however, is always negative no matter where the ball is in its motion. This negative acceleration causes the ball to slow down as it reaches the top, and speed up as it reaches the bottom.

Think about it: If there wasn't a negative acceleration, and it was instead 0, the ball would never come back down and instead keep going in a straight line.

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2 years ago

Read 2 more answers

A boy pushes a cart with a constant velocity of 0.5m/s by applying a force of 60 N. What is the total frictional force acting on

Nutka1998 [239]

Answer:

60N

Explanation:

in this case the minimum amount of force required must be equal to the friction Force. i.e Newton's first law of motion.

therefore the maximum amount of frictional force is equal to the applied force which is 60N.

because of the net force acting on the object is zero the object is in constant motion . i.e equal and opposite force must be applied so that the object is in constant velocity therefore the total frictional force must be 60N

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3 years ago