Answer:
Among others, two adaptations might be
- Avoiding corporal heat loss
- Increasing oxygen absorption
Explanation:
Up in the mountains, there is low oxygen, food is scarce, and adverse meteorological conditions. Animals and plants need to develop different strategies to survive. These adaptations involve not only physical and physiological changes but also behavioral changes. To mention a few adaptations, we can name:
- Avoiding heat loss. Temperature tends to be very low at highs, so, to <u>avoid heat loss,</u> animals develop shorter legs, tails, and ears. By doing this they reduce the area or surface of heat loss and also avoid getting frozen. In mammals, the coat is also very important. A thick coat helps them maintain a constant body temperature and keep warm. Some amphibians might also develop a thicker skin as they can not regulate their temperature, and it also helps them not to dehydrate.
- Camouflage: Coat is also helpful in camouflaging. Mammals´ hair color depends on their environment. Some animals, such as hares, can also change their fur color depending on the season. During snow seasons they turn white, and during the warmer season, they turn yellow or brown.
- Size and metabolism: Small mammals lose heat very fast, so they need to keep active and feeding most of the time. They have an elevated metabolism to keep warm. On the contrary, big animals, such as bears, need to hibernate to reduce their metabolism and get to survive, otherwise, they would need many reserves to cover their energetic requirements.
- Oxygen absorption: Some animals have adapted to the lack of oxygen by increasing their heart and lungs capacity as well as their capability to absorbing more oxygen from the blood.
Answer:
The diagram is attached below.
Explanation:
when sodium and chlorine comes close together they form anion and cation. The compound formed is called sodium chloride.
Both atoms bonded together through ionic bond.
Ionic bond:
It is the bond which is formed by the transfer of electron from one atom to the atom of another element.
Both bonded atoms have very large electronegativity difference. The atom with large electronegativity value accept the electron from other with smaller value of electronegativity.
For example:
Sodium chloride is ionic compound. The electronegativity of chlorine is 3.16 and for sodium is 0.93. There is large difference is present. That's why electron from sodium is transfer to the chlorine. Sodium becomes positive and chlorine becomes negative ion.
Answer:
Swishing sound.
Explanation:
Human heart produces unique sound when blood flows from one chamber to the next chamber. The two main sounds produced by heart are lub abd dub sound.
The doctor's examine the Janetta's heart and told that she has incompetent right atrioventricular valve. The doctor must have heard the swishing sound after the closing of right atrioventricular valve. This sound is the direct indication of incompetent AV valve.
Joint hypermobility syndrome (JHS) and Ehlers-Danlos syndrome, hypermobility type (EDS-HT) are the tissue disorders which can be characterized by chronic pain, joint instability complications, and minor skin changes. During these, Fatigue and headache are the very common symptoms; though they can be diagnosed using specific criteria.
JHS/EDS-HT is a rare common condition that could not be diagnosed by most clinicians and pain specialists, resulting in interventions like symptomatic and non-satisfactory treatments, because there is a lack of reasonable pathophysiologic rationale.
Pain, fatigue, and headache in JHS/EDS are usually treated with the help of certain symptoms or on the basis of doctors’ experience.
<span>Therefore, in order to the cure of such symptoms, doctors suggest pathogenic mechanisms. The major aim of the re-writing of the natural history of JHS/EDS-HT is to raise awareness among clinical geneticists and specialists treating chronic pain conditions about pain and other complications of JHS/EDS-HT.</span>
Answer:
0%
Explanation:
The cross of a pea plant with round seeds (RR) with another pea plant with wrinkled seeds (rr) is shown as under :
P RR x rr
F1 Rr Rr Rr Rr
It is clear from the cross above, all the 4 probable progenies in filial 1 (F1) generation will be heterozygous with Rr genotype. Not even a single progeny will have homozygous recessive genotype which is responsible for producing wrinkled seeds. Also, even though the genotype of the progenies will be Rr not RR yet phenotypically they all will have round seeds i.e. they will show dominant trait. The reason behind it is that one of the alleles R which is responsible for dominant trait will mask the expression of recessive allele r. So, wrinkled phenotype which is a recessive trait will not be observed in any of the progenies.
