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Georgia [21]
2 years ago
13

What is one factor that makes women more susceptible than men to urinary tract infections?​?

Biology
1 answer:
lubasha [3.4K]2 years ago
8 0
One  of  the  factor  that  make  women   more  susceptible  than  men  to  urinary  tract  infection  is  because  male  have   longer   urethra  while  female  have  shorter  urethra.this  make  infectious  agent  to  reach  the bladder  more  easily  through   the  short  female  urethra  than  through  the  longer  male  urethra.women   are  affected 50-60  times  as  often  to  men
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Normally, the hydrostatic pressure difference between capillary fluid and interstitial fluid favors movement of fluid __________
timofeeve [1]

Answer:

out of

into

Explanation:

As pressure exerts force, Hydrostatic pressure is a type of force that occurs in fluid e.g (interstitial fluids) on the walls of the capillary. The helps to carry fluid-like materials out of the tissue capillary. There are quite bunch of relative factors affecting the hydrostatic pressure which include; the liquid density and distance beneath the liquid surface,force of gravity.

On the other hand, The protein osmotic pressure difference between capillary fluid and interstitial fluid normally favors movement of fluid into a tissue capillary. This protein substances consist of albumin, plasma protein etc. From our knowledge of osmosis as well, we knew it is the movement of substances through a semi-permeable membrane from the region of higher concentration to a lower concentration.  Therefore the protein osmotic pressure bring about movement of fluid like substances into the tissue capillary.

7 0
3 years ago
What factor slows transcription?
Leya [2.2K]

Repressor slows down transcription.

RNA Polymerase enzyme transcribes mRNA from DNA.

Explanation:

Promoters are the 100 to 900 bps long sequence of DNA, that helps in the initiation of transcription. The transcription gets slow down as repressor bind to the promoter region hampering the attachment of RNA Polymerase enzyme which is responsible for transcription.

The process of transcription is the conversion of DNA into mRNA as told in the central dogma of molecular biology. Enzyme responsible for transcription is RNA polymerase. It is the first phase of gene expression, where DNA strand is copied into mRNA called a primary transcript.

7 0
3 years ago
Explain how we know that DNA breaks and rejoins during recombination.
alisha [4.7K]

Answer:

It occurs through homologous recombination

Explanation:

GENERAL RECOMBINATION OR HOMOLOGIST

           Previously we defined its general characteristics. We will now describe a molecular model of this recombination, based on the classic Meselson and Radding, modified with the latest advances. Do not forget that we are facing a model, that is, a hypothetical proposal to explain a set of experimental data. Not all points of this model are fully clarified or demonstrated:

           Suppose we have an exogenote and an endogenote, both consisting of double helices. In recombination models, the exogenote is usually referred to as donor DNA, and the endogenote as recipient DNA.

1) Start of recombination: Homologous recombination begins with an endonucleotide incision in one of the donor double helix chains. Responsible for this process is the nuclease RecBCD (= nuclease V), which acts as follows: it is randomly attached to the donor's DNA, and moves along the double helix until it finds a characteristic sequence called c

Once the sequence is recognized, the RecBCD nuclease cuts to 4-6 bases to the right (3 'side) of the upper chain (as we have written above). Then, this same protein, acting now as a helicase, unrolls the cut chain, causing a zone of single-stranded DNA (c.s. DNA) to move with its 3 ’free end

2) The gap left by the displaced portion of the donor cut chain is filled by reparative DNA synthesis.

3) The displaced single chain zone of the donor DNA is coated by subunits of the RecA protein (at the rate of one RecA monomer per 5-10 bases). Thus, that simple chain adopts an extended helical configuration.

4) Assimilation or synapse: This is the key moment of action of RecA. Somehow, the DNA-bound RecA c.s. The donor facilitates the encounter of the latter with the complementary double helix part of the recipient, so that in principle a triple helix is formed. Then, with the hydrolysis of ATP, RecA facilitates that the donor chain moves to the homologous chain of the receptor, and therefore matches the complementary one of that receptor. In this process, the chain portion of the donor's homologous receptor is displaced, causing the so-called "D-structure".

It is important to highlight that this process promoted by RecA depends on the donor and the recipient having great sequence homology (from 100 to 95%), and that these homology segments are more than 100 bases in length.

Note that this synapse involves the formation of a portion of heteroduplex in the double receptor helix: there is an area where each chain comes from a DNA c.d. different parental (donor and recipient).

5) It is assumed that the newly displaced chain of the recipient DNA (D-structure) is digested by nucleases.

6) Covalent union of the ends originating in the two homologous chains. This results in a simple cross-linking whereby the two double helices are "tied." The resulting global structure is called the Holliday structure or joint.

7) Migration of the branches: a complex formed by the RuvA and RuvB proteins is attached to the crossing point of the Holliday structure, which with ATP hydrolysis achieve the displacement of the Hollyday crossing point: in this way the portion of heteroduplex in both double helices.

8) Isomerization: to easily visualize it, imagine that we rotate the two segments of one of the DNA c.d. 180o with respect to the cross-linking point, to generate a flat structure that is isomeric from the previous one ("X structure").

9) Resolution of this structure: this step is catalyzed by the RuvC protein, which cuts and splices two of the chains cross-linked at the Hollyday junction. The result of the resolution may vary depending on whether the chains that were not previously involved in the cross-linking are cut and spliced, or that they are again involved in this second cutting and sealing operation:

a) If the cuts and splices affect the DNA chains that were not previously involved in the cross-linking, the result will be two reciprocal recombinant molecules, where each of the 4 chains are recombinant (there has been an exchange of markers between donor and recipient)

b) If the cuts and splices affect the same chains that had already participated in the first cross-linking, the result will consist of two double helices that present only two portions of heteroduplex DNA.

8 0
3 years ago
1+1=?<br>"only wrong answer"​
hoa [83]
5 Windows, 3 ants, 36 closets
4 0
2 years ago
Which of following is a use for fossils found in sedimentary rocks?
Greeley [361]

Answer:

i am pretty sure it would be B. All the above... not positive though

Explanation:

tell if wrong.... have a nice day!

7 0
2 years ago
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