Question

A ball is thrown upward at time t=0 from the ground with an initial velocity of 4 m/s (~ 9 mph). Assume that g = 10 m/s^2. What is the greatest height (in meters) reached by the ball?

Answer 1

Answer:

The greatest height reached by the ball is 0.8 m.

Explanation:

Given that,

Initial velocity = 4 m/s

We need to calculate the greatest height reached by the ball

Using equation of motion

$v^2=u^2+2gh$

Where, v = final velocity

u = initial velocity

g = acceleration due to gravity

Put the value in the equation

$0=4^2+2\times(-10)\times h$

$h =\dfrac{16}{20}$

$h =0.8\ m$

Hence, The greatest height reached by the ball is 0.8 m.