Ask question

Ask question

All categories

3 years ago

9

Ou are given a 25.3 µf capacitor that is connected to a 13.0 v dc power supply. what will be the charge that is stored on this c

apacitor when it is fully charged?

1 answer:

Black_prince [1.1K]3 years ago

5 0

charge stored in the capacitor=3.29 x 10⁻⁴ C

Explanation:

we use the formula

Q= C V

Q= charge

C= capacitor=25.3 μF= 25.3 x 10⁻⁶ F

V= voltage= 13 V

Q=(25.3 x 10⁻⁶ ) (13)

Q= 3.29 x 10⁻⁴ C

You might be interested in

A 100 kg cart goes around the inside of a vertical loop of a roller coaster. The radius of the loop is 3 m and the cart moves at

Sphinxa [80]

Answer:

200 N

Explanation:

8 0

3 years ago

What’s the answer please?

photoshop1234 [79]

Answer:

C

Explanation:

Hope this helps!

8 0

3 years ago

What Is meant By MA of a machine is 2?

stich3 [128]

Answer:

See below ~

Explanation:

The Mechanical Advantage (MA) is defined as the ratio between the force produced by the machine to the force applied to it.

=============================================================

So,

⇒ $\frac{F(out)}{F(in)} = 2$

⇒ This means that the force produced is twice the applied force

7 0

2 years ago

Reyna kicks a ball, which then rolls across a grassy field. Which is the best explanation for why the ball eventually comes to a

nataly862011 [7]

Short Answer- Friction

Explanation- There is friction between the grass and the ball. Friction is a type of force that limits motion between two surfaces that are touching. Friction is the force that one surface exerts on another with the two surfaces rubbing together.

This is the answer, hope it helps :)

8 0

3 years ago

Two identical metal spheres a and b are connected by a plastic rod. both are initially neutral. 1.0×1012 electrons are added to

Ann [662]

The plastic rod is made of insulator (plastic), so it does not allow charges moving from one sphere to another. This means that all the electrons given to sphere A will remain on sphere A.

The number of electrons initially given to sphere A is $N=1.0 \cdot 10^{12}$ , and since the charge of 1 electron is $e=-1.6 \cdot 10^{-19} C$ , the net charge left on sphere A after the removal of the rod will be
$Q=N e = 1.0 \cdot 10^{12}(-1.6 \cdot 10^{-19} C)=-1.6.0 \cdot 10^{-7} C$

8 0

3 years ago

Read 2 more answers