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arsen [322]
3 years ago
9

Ou are given a 25.3 µf capacitor that is connected to a 13.0 v dc power supply. what will be the charge that is stored on this c

apacitor when it is fully charged?
Physics
1 answer:
Black_prince [1.1K]3 years ago
5 0

charge stored in the capacitor=3.29 x 10⁻⁴ C

Explanation:

we use the formula

Q= C V

Q= charge

C= capacitor=25.3 μF= 25.3 x 10⁻⁶ F

V= voltage= 13 V

Q=(25.3 x 10⁻⁶ ) (13)

Q= 3.29 x 10⁻⁴ C

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Answer:

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Explanation:

1) Los parámetros dados son;

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Por lo tanto, tenemos;

El área de la base del cilindro = π · r² = 13122000 cm³ / (20 cm) = 656100 cm²

r = √ (656100 / π) ≈ 456,994 cm

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La fuerza del cilindro = 5576850 kgf

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Question 5 of 10
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