Answer:
14.625 years
Explanation:
Because acceleration/deceleration are negligent we can simplify this problem into 2 basic parts:
First: how long before the astronaut arrives? Since the speed of the craft is 0.8 times the speed of light and the distance to travel is 6.5 light-years, the equation to answer this part is:
0.8t=6.5
solve for t by dividing by 0.8
t=6.5/0.8 or 8.125
so, she will arrive in 8.125 years.
Then, once she sends her message, it will travel towards earth at 1 times the speed of light or:
1.0t=6.5 which is just t=6.5
so, her message will arrive back to Earth (8.125+6.5) 14.625 years after takeoff.
Answer:
1. :uniformly accelerated motion
2. .0m/s
Answer:
Option B. 1,100 Earth diameters
Solution:
Angular position of steroid,
(given)
To calculate the distance of asteroid, we use parallax method given as:
(1)
where,
From the relation:
l = ![\theta \times R](https://tex.z-dn.net/?f=%5Ctheta%20%5Ctimes%20R)
we get:
distance(d) or R = ![\frac{Earth diameter}{\theta}](https://tex.z-dn.net/?f=%5Cfrac%7BEarth%20diameter%7D%7B%5Ctheta%7D)
distance(d) or R = ![\frac{2\times radius of earth}{\theta}](https://tex.z-dn.net/?f=%5Cfrac%7B2%5Ctimes%20radius%20of%20earth%7D%7B%5Ctheta%7D)
d = ![\frac{2\times 6350000}{8.726\times 10^{-4}}](https://tex.z-dn.net/?f=%5Cfrac%7B2%5Ctimes%206350000%7D%7B8.726%5Ctimes%2010%5E%7B-4%7D%7D)
distance, d = ![1.455\times 10^{10} m](https://tex.z-dn.net/?f=1.455%5Ctimes%2010%5E%7B10%7D%20m)
Comparing it with Earth's diameter:
d = ![\frac{1.455\times 10^{10}}{2\times 6350000} = 1,146](https://tex.z-dn.net/?f=%5Cfrac%7B1.455%5Ctimes%2010%5E%7B10%7D%7D%7B2%5Ctimes%206350000%7D%20%3D%201%2C146)
Since, the value is close to 1,100 Earth diameters, therefore, option B is the right answer.
Resistance is current x potential difference. So therefor run wafff