3 years ago

Question 4 (5 points)

Physics

1 answer:

faust18 [17]3 years ago

8 0

The domains in a magnet are aligned according to magnetic fields.

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A loop of wire in the shape of a rectangle rotates with a frequency of 219 rotation per minute in an applied magnetic field of m

bazaltina [42]

Answer:

Emax = 0.055V

Imax = 7.86mA

Explanation:

See attachment below.

6 0

2 years ago

What is the total energy of a particle with a rest mass of 1 gram moving with half the speed of light? 1 eV = 1.6 x 10^-19 J. An

GREYUIT [131]

Answer:

6.5 x 10^32 eV

Explanation:

mass of particle, mo = 1 g = 0.001 kg

velocity of particle, v = half of velocity of light = c / 2

c = 3 x 10^8 m/s

Energy associated to the particle

E = γ mo c^2

$E=\frac{m_{0}c^}2}{\sqrt{1-\frac{v^{2}}{c^{2}}}}$

$E=\frac{m_{0}c^}2}{\sqrt{1-\frac{c^{2}}{4c^{2}}}}$

$E=\frac{2m_{0}c^}2}{\sqrt{3}}$

$E=\frac{2\times0.001\times9\times10^{16}}{1.732}$

$E=1.04\times10^{14}J$

Convert Joule into eV

1 eV = 1.6 x 10^-19 J

So, $E=\frac{1.04\times10^{14}}{1.6\times10^{-19}}=6.5\times10^{32}eV$

4 0

2 years ago

In an engine governor, the two spheres (total mass of 1.0kg) are at 0.05m and rotating at 37rad/s If the engine increases the an

kirill115 [55]

Here we can say that there is no external torque on this system

So here we can say that angular momentum is conserved

so here we will have

$I_1\omega_1 = I_2\omega_2$

now we have

$I_1 = mr^2$

$I_1 = (1kg)(0.05^2)$

$I_1 = 25\times 10^{-4} kg m^2$

similarly let the final distance is "r"

so now we have

$I_2 = mr^2$

$I_2 = 1r^2$

now from above equation we have

$(25\times 10^{-4})37 = (r^2)(58)$

$r = 0.04 m$

so final distance is 0.04 m between them

8 0

2 years ago

10 points please somebody help me

Anuta_ua [19.1K]

It is the first one?

7 0

3 years ago

Read 2 more answers

Determine the force of gravity or weight of each of the following objects or systems. Use

Inessa05 [86]

Answer:

1: 19,6 N | 2: 686 N | 3: 705,6 N

Explanation:

Just apply the formula:

1: 2 . 9,8 = 19.6 N

2: (60+10) . 9,8 = 686 N

3: [30 + (6 . 7)] . 9,8

[30 + 42] . 9,8

72 . 9,8 = 705.6 N

Just sum all the weights in the system and then multiply by gravity (9,8 in this case)

4 0

3 years ago