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Natasha2012 [34]
3 years ago
6

A loop of wire in the shape of a rectangle rotates with a frequency of 219 rotation per minute in an applied magnetic field of m

agnitude 6 T. Assume the magnetic field is uniform. The area of the loop is A = 4 cm2 and the total resistance in the circuit is 7 Ω.
Find the maximum induced emf.
e m fmax =_______

Find the maximum current through the bulb.
Imax=__________

Physics
1 answer:
bazaltina [42]3 years ago
6 0

Answer:

Emax = 0.055V

Imax = 7.86mA

Explanation:

See attachment below.

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1.15) What distance will 650 joules of work move a box weighing 50 newtons?​
son4ous [18]

Answer:

The answer is 13 however make sure if they ask for a certain measurement like meter answer it by saying 13 meters.

Explanation:

This basically turns into basic algebra if you know the formula for work. The formula for work is W=F*d  

Here are the variables that you know 650J=50N*d so you need d.

All you do is divide 650J by 50N and you get a total of 13 (meters since I don't know what they want you to put it in).

6 0
3 years ago
A group of students launches a model rocket in the vertical direction. Based on tracking data, they determine that the altidude
Serjik [45]

Answer:

a) 252 ft/s

b) 1076 ft

Explanation:

The equation for motion for uniform acceleration (we can use it because the rocket is affected only by gravity) is as follows:

Y(t) = Y0 + V0 * t + 1/2 * a * t^2

Where

Y(t): altitude at a given time

Y0: initial altitude

V0: initial speed

a: acceleration, in this case -32.2 ft/s^2 (negative because gravity points down)

We set a 1 dimensional coordinate system with Y pointing up and the origin of coordinates at ground level.

We consider t=0 as the moment where powered flight ended (motor ran oou of fuel), at this moment the altitude was

Y(0) = 89.6 ft

Therefore:

Y0 = 89.6 ft

We also know that the rocket fell to ground 16 seconds later, therefore

Y(16) = 0 ft

So we can write

Y(t=16) = Y0 + V0 * t + 1/2 * a * t^2

V0 * t = Y(t=16) - Y0 - 1/2 * a * t^2

V0 =( Y(t=16) - Y0 - 1/2 * a * t^2 )/t

V0 =( 0 - 89.6 - 1/2 * (-32.2) * 16^2 )/16 = 252 ft/s

In the highest point of flight the rocket will have a speed = 0

The first derivative of the equation of motion is the equation of speed:

V(t) = V0 + a * t

If we equate this to zero we eill find the time at which the rocket achieved it's highest altitude.

0 = V0 + a * t

a * t = 0 - V0

t = -V0/a

t = -252/(-32.2) = 7.83 s

Now, we can take this time value andd plug it back into the position equation

Y(7.83) = 89.6 + 252 * 7.83 + 1/2 * (-32.2) * 7.83^2 = 1076 ft

6 0
3 years ago
If a stone dropped into a well reaches the water's surface after 3.0 seconds, how far did the stone drop before hitting the wate
Ulleksa [173]
<span>s= 0.5 at^2
</span>
0.5 x 9.81 x 3^2 = 44m
8 0
3 years ago
Read 2 more answers
A box with the mass of 20 kg at 5 m is lifted to 20 m. How much work was 7 points<br> done?
kirza4 [7]

Answer:

2,900\: \mathrm{J}

Explanation:

Work is given by the equation W=F\Delta x where F is force and \Delta x is displacement.

Displacement is defined as change in position. In this case, the box moves from 5m to 20m. Its displacement is 20-5=15\:\mathrm{m}.

The force acting on the box is the force of gravity, given as F_g=mg.

Therefore, the total work done is:

W=F\Delta x=mg\Delta x = 20\cdot 9.81\cdot 15=2,943=\fbox{$2,900\:\mathrm{J}$}(two significant figures).

3 0
3 years ago
According to the electromagnetic spectrum,
olga_2 [115]
A. long-wave radiation occupies a smaller percentage than short-wave radiation
5 0
4 years ago
Read 2 more answers
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